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Marizza181 [45]
3 years ago
5

What is the domain of the function y= x +4? -0 -4 O 0 4

Mathematics
1 answer:
Jet001 [13]3 years ago
5 0

Answer:

the third option is correct

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PLEASE PLEASE PLEASE PLEASE HELP ME WITH GEOMETRY!!!
Sergio [31]
I think it would be 370
6 0
3 years ago
George would like to build a garden this year, George measure out his proposed garden and would like to know how many square fee
Blababa [14]

Answer:

The area is 105.5ft^2

Step-by-step explanation:

Required

The area of the composite figure

The figure can be divided to 2 shapes

(1) Rectangle: Length = 6ft and Width = 8ft

(2) Trapezoid: Height = 5ft (i.e. 8 - 3), Parallel sides = 9ft and 14ft (i.e. 20 - 6)

The area of the rectangle is:

Area = 6 * 8 = 48

The area of the trapezoid is:

Area = \frac{1}{2}(9 + 14) * 5

Area = \frac{1}{2}(23) * 5

Area = 11.5 * 5

Area = 57.5

So, the area of the garden is:

Total = 48 + 57.5

Total = 105.5

5 0
3 years ago
How do science and math relate to each other?
madreJ [45]
Many if not all sciences require math at some point whether it be measurements of chemicals, balancing chemical reactions, plotting data for how often a certain animal does a certain thing, how much of a medicine to give a patient to cure their ailment but not cause any side effects, etc. etc. 
4 0
3 years ago
A student at a four-year college claims that average enrollment at four-year colleges is higher than at two-year colleges in the
Kitty [74]

Answer:

a) Since we have sample data and we don't know the population deviation we can use the t distribution in order to test the hypothesis

t would represent the statistic

b) t=\frac{(\bar X_{2}-\bar X_{1})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)  

The degrees of freedom are given by df=n_1 +n_2 -2=35+35-2=68  Replacing the info given we got:

t=\frac{(5216-5069)-0}{\sqrt{\frac{4773^2}{35}+\frac{8141^2}{35}}}}=0.0921  

c) p_v =P(t_{68}>0.0921)=0.463  

Since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean of enrollment is significantly higher for four year college than for two year college

Step-by-step explanation:

Information given

\bar X_{1}=5069 represent the mean for two year colleges

\bar X_{2}=5216 represent the mean for four year college

s_{1}=4773 represent the sample standard deviation for 1  

s_{2}=8141 represent the sample standard deviation for 2  

n_{1}=35 sample size for the group 2  

n_{2}=35 sample size for the group 2  

\alpha=0.05 Significance level provided

Part a

Since we have sample data and we don't know the population deviation we can use the t distribution in order to test the hypothesis

t would represent the statistic

Part b

We want to test if the mean of enrollment for four year college is higher than for two year college, the system of hypothesis would be:  

Null hypothesis:\mu_{2}-\mu_{1} \leq 0  

Alternative hypothesis:\mu_{2} - \mu_{1} > 0  

The statistic is given by:

t=\frac{(\bar X_{2}-\bar X_{1})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)  

The degrees of freedom are given by df=n_1 +n_2 -2=35+35-2=68  Replacing the info given we got:

t=\frac{(5216-5069)-0}{\sqrt{\frac{4773^2}{35}+\frac{8141^2}{35}}}}=0.0921  

Part c

The p value would be given by:

p_v =P(t_{68}>0.0921)=0.463  

Since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean of enrollment is significantly higher for four year college than for two year college

6 0
4 years ago
What expression is equivalent to 5(x-0.8)
astra-53 [7]

Answer:

5x-4

Step-by-step explanation:

$#$$$$$$$$$$$$$

5 0
4 years ago
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