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3 years ago

Determine the correct scientific notation form of the number. 627,000,000

Mathematics

1 answer:

GREYUIT [131]3 years ago

8 0

Answer:

6.27 x 10 ^ 8

Step-by-step explanation:

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Chay throws an object straight up into the air with an initial velocity of 60 ft/s from a platform that is 40 ft above the groun

Mila [183]

The object will hit the ground in 4.3 s.

The formula used for the object thrown by Chay is:

$h(t)=-16t^{2}+v_{0}t+h_{0}$

According to the problem,

Initial velocity $v_{0}=60ft/s$

Initial height $h_{0}=40ft$

Therefore,

$h(t)=-16t^{2}+60t+40$

When the object hits the ground h(t) becomes 0.

Thus,

$0=-16t^{2}+60t+40$

Dividing both sides by 4 we get;

$4t^{2}-15t-10=0$

Solving by applying quadratic formula;

$x=\frac{-b+/-\sqrt{b^{2-4ac} } }{2a}$

$t=\frac{15+/-\sqrt{15^{2}+160 } }{8}$

t=4.3s

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4 years ago

A/4 + 2 = 6 &' -4 = r/20 - 5 can u please help me on these two

statuscvo [17]

A/4 + 2 = 6....subtract 2 from both sides
A/4 = 6 - 2
A/4 = 4...multiply both sides by 4, eliminating the 4 on the left side
A = 4 * 4
A = 16

-4 = r/20....multiply both sides by 20, eliminating the 20 on the right side
-4 * 20 = r
-80 = r

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3 years ago

Why do scientist collect data

julsineya [31]

As scientists conduct their research, they make observations and collect data. The observations and data often lead them to ask why something is the way it is. Scientists pursue answers to these questions in order to continue with their research.

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3 years ago

Answer this question

iris [78.8K]

Answer:

I believe it is c.

...........

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3 years ago

Adimas found the mean of her 11 math test scores for the first semester. X = StartFraction (76 87 65 88 67 84 77 82 91 85 90) Ov

Reika [66]

To find the solution we will first find the difference between each number and mean, and then substitute the value in the formula of standard deviation.

The standard deviation is 8.4477 and the variance is 71.40.

Given to us

Test scores of Adimas = (76, 87, 65, 88, 67, 84, 77, 82, 91, 85, 90)
Mean = 81

<h3>Standard Deviation</h3>

difference between each number and mean,

$x_1 -\mu= 76-81 = -5\\
x_2-\mu = 87-81 = 6\\
x_3-\mu = 65-81 = -16\\
x_4-\mu = 88 -81 = 7\\
x_5-\mu = 67-81 = -14\\
x_6 -\mu= 84-81 = 3\\
x_7 -\mu= 77-81 = -4\\
x_8 -\mu= 81-81 = 1\\
x_9 -\mu= 91-81 = 10\\
x_{10}-\mu=85-81 = 4\\
x_{11} -\mu= 90-81 = 9$