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marshall27 [118]
3 years ago
10

What is the value of f(x)=-4 ?

Mathematics
1 answer:
Gala2k [10]3 years ago
7 0
Answer : 2

Step by step walkthrough:
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The unit digit of square of the square of the number 42 is <br>​
cupoosta [38]
Um so 42 squared is 1764 and 1764 squared is 3111696 so then 6 is the unit digit
7 0
3 years ago
Multiply the trinomial x^2+xy+y^2 times the binomial x-y and simplify.
Natalija [7]
Multiply then simplify, that's doing the same work twice...anyway

x^3+x^2y+xy^2-x^2y-xy^2-y^3

x^3-y^3  which if factored is:

(x-y)(x^2+xy+y^2)  which is what you started with :)
6 0
3 years ago
To most closely estimate the difference below, would you round the numbers to the nearest ten thousand, the nearest thousand, or
zhannawk [14.2K]

Answer:

To most closely estimate the difference, I would round 62,980 to the nearest thousand, so it will be 63,000. That is because when rounding, 63,000 is large enough so that adding will be easy, and 62,980 is relatively close to 63,000.

I would round 49,625 to the nearest thousand, since it would make the subtraction easier and 49,625 is only 375 units away from 50,000.

63,000 - 50,000 = about 13,000.

Hope this helps!

6 0
3 years ago
Read 2 more answers
Expand each expression
matrenka [14]

Answer:

Option B - \ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Step-by-step explanation:

Given : Expression \ln(\frac{4y^5}{x^2})

To find : Expand each expression ?

Solution :

Using logarithmic properties,

\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B

and \ln (AB)=\ln A+\ln B

Here, A=4y^5 and B=x^2

\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}

\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2

\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2

Using logarithmic property, \logx^a=a\log x

\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Therefore, option B is correct.

3 0
3 years ago
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Divide. Write your answer using the smallest numbers possible.
Ilya [14]

Answer:

30660

Step-by-step explanation:

8 0
3 years ago
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