She will now save $56 every month. Please Mark Brainliest!!!
Answer:
a) $1520
b)
$209195
Step-by-step explanation:
The range of salaries forms an arithmetic sequence with the first term as 25325 and its 7th term as 34445:
a) The raise the person can get each year is the common difference of the progression, d.
The nth term of an arithmetic progression is given generally as:

where a = first term = 25325
d = common difference
Therefore, the 7th term (34445) will be:
34445 = 25325 + (7 - 1)d
34445 = 25325 + 6d
=> 6d = 34445 - 25325 = 9120
d = 9120 / 6 = $1520
Therefore, the raise the person gets each year (common difference) is $1520.
b) The total amount the person will earn after 7 years is the sum of the salaries of all 7 yeas.
The sum of an arithmetic progression up to the nth term is given as:

Therefore, the sum of the person's salary for the 7 years is:

$209195
That is the total amount of salary after 7 years

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<u>we've</u><u> </u><u>been </u><u>given </u><u>the </u><u>two </u><u>sides </u><u>of </u><u>the </u><u>rectangle </u><u>and </u><u>we're</u><u> </u><u>required</u><u> </u><u>to </u><u>find </u><u>out </u><u>the </u><u>height </u><u>of </u><u>the </u><u>triangle </u><u>,</u><u> </u><u>so </u><u>as </u><u>to </u><u>find </u><u>it's</u><u> </u><u>area </u><u>~</u>
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<h3><u>For </u><u>perimeter</u><u> </u><u>of </u><u>the </u><u>figure </u><u>-</u></h3>

now ,
<u>perimeter</u><u> </u><u>of </u><u>rectangle </u><u>=</u><u> </u><u>2</u><u> </u><u>(</u><u> </u><u>l </u><u>+</u><u> </u><u>b </u><u>)</u>
where ,
<u>l </u><u>=</u><u> </u><u>length </u>
<u>b </u><u>=</u><u> </u><u>breadth </u>

and ,

<u>Perimeter</u><u> </u><u>of </u><u>figure </u><u>in </u><u>total </u><u>=</u><u> </u><u>2</u><u>6</u><u> </u><u>cm </u><u>+</u><u> </u><u>1</u><u>5</u><u> </u><u>cm</u>
thus ,

<h3><u>For </u><u>area </u><u>of </u><u>the </u><u>figure </u><u>-</u></h3>

now ,
<u>area </u><u>of </u><u>rectangle</u><u> </u><u>=</u><u> </u><u>l </u><u>×</u><u> </u><u>b</u>
where ,
<u>l </u><u>=</u><u> </u><u>length </u>
<u>b </u><u>=</u><u> </u><u>breadth</u>

and ,

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thus ,

hope helpful :)