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svetoff [14.1K]
3 years ago
5

Ernesto drew a map of his school.He used a scale of 1 inch:50 feet.what distance in inches on Ernesto’s map should represent the

625 feet between the cafeteria and the science lab
Mathematics
1 answer:
KatRina [158]3 years ago
3 0
12 and 1/4 Inches is the distance between the cafeteria and the science lab
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How do you add (− 3c4 − 5c2 − 7c) + (4c4 + 8c3 + 2c2)
scZoUnD [109]

Answer:

c4+8c3+−3c2+−7c

Step-by-step explanation:

Let's simplify step-by-step.

−3c4−5c2−7c+4c4+8c3+2c2

=−3c4+−5c2+−7c+4c4+8c3+2c2

Combine Like Terms:

=−3c4+−5c2+−7c+4c4+8c3+2c2

=(−3c4+4c4)+(8c3)+(−5c2+2c2)+(−7c)

=c4+8c3+−3c2+−7c

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2 years ago
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Let h = for 0   0.01 m, and h = for   0.01 m. (a) find j everywhere. (b) what is j at  = 0? (c) is there a filamentary cu
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3 years ago
A bakery wants to determine how many trays of doughnuts it should prepare each day. Demand is normal with a mean of 5 trays and
Alexeev081 [22]

Answer:

4 trays should he prepared, if the owner wants a service level of at least 95%.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5

Standard Deviation, σ = 1

We are given that the distribution of demand score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(X > x) = 0.95

We have to find the value of x such that the probability is 0.95

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 5}{1})=0.95  

= 1 -P( z \leq \displaystyle\frac{x - 5}{1})=0.95  

=P( z \leq \displaystyle\frac{x - 5}{1})=0.05  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 5}{1} = -1.645\\x = 3.355 \approx 4  

Hence,  4 trays should he prepared, if the owner wants a service level of at least 95%.

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