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2 years ago

Does anyone have remind ill give u a code

Mathematics

2 answers:

Tanya [424]2 years ago

7 0

Answer:

can i has code

Step-by-step explanation:

i can give u memes

NeTakaya2 years ago

6 0

Answer:

Step-by-step explanation:

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A ball rolled from Point A to Point B in 18 second at a speed of 14 m/s. IT took another 18 seconds to roll form Pint B to Pint

vaieri [72.5K]

Answer:

d=252m, u dint put the speed it was rolling at from point B to C so I could only solve for A to B. However if you use the formula below you can find the distance from B to C and add that to A to B giving the total distance rolled.

Step-by-step explanation:

d=vt

v=14m/s

t=18s

d= vt, (14m/s)(18s)

d=252m

8 0

3 years ago

Read 2 more answers

Graph the ellipse with equation x^2 /25 + y^2 /4 = 1.

nexus9112 [7]

Center: 0,0
vertex: 5,0
vertex2 (-5,0)

4 0

3 years ago

Please help ASAP!!!!!!!

aleksklad [387]

Answer:

i think 1st no. option but i am not sure

5 0

3 years ago

What is the area of this figure? Enter your answer in the box.

Basile [38]

Luckily for us, the diagram already divided this figure into separate polygons. What I will be explaining is basically the addition of the areas of all the separate polygons. The area of the uppermost triangle is:

1/2 x b x h
= 1/2 x 20 x 8
(the base is 20, because in a parallelogram, opposite sides are congruent)
=10 x 8
= 80 in. squared

The next polygon we will be taking the area of is the parallelogram with the base length of 20 and the height of 16.

Area = b x h
= 20 x 16
= 320 in. squared

Now all we have left to do is add the two areas to obtain the total area.

Total Area = 320 + 80 = 400 in. squared

3 0

3 years ago

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago