If the right triangle has legs with lengths 42 m and 34 m and the hypotenuse with length 54 m, then you need:
1. P=42+34+54=130m (perimeter) of <span>new curbing to go around the space between three streets;
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<span>2.
sq. m. (area) of </span><span>sod to cover the space.
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All given choices are right.
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A. His answer is incorrect. 2 cubed is 2 X 2 X 2, which is 8. Add 4 and you have the answer of 12.
B. He may have multiplied 2 X 3 and then added 4, instead of multiplying 2 three times.
constant of proportionality => COP
3: P(triangle ABC) = 84
COP = 18/15 = 1.2
Since you are finding the larger triangle, multiply the other numbers by 1.2
25 * 1.2 = 30
28 * 1.2 = 33.6
17 * 1.2 = 20.4
add them all up (answer up top)
5: P(triangle ABC) = 61.2
COP = 9/5 = 1.8
Since you are finding the larger triangle, multiply the other numbers by 1.8
9 * 1.8 = 16.2
13 * 1.8 = 23.4
12 * 1.8 = 21.6
add them all up (answer up top)
6: P(triangle RST) = 110
RP and PT are congruent, this means that PT is also 20
COP = 40/20 = 2
Since you are finding the larger triangle, multiply the other numbers by 2
25 * 2 = 50
20 * 2 = 40
10 * 2 = 20
add them all up (answer up top)
6.5%=.065
.065/12=0.00541666666666666666666666666667/month
3 years = 36 months
(1+0.00541666666666666666666666666667)^36=1.2146716269797335689295444127607
1.2146716269797335689295444127607 x 12500=$15183.40 in the account after 3 years
15183.40-12500=$2683.40 in interest earned
☺☺☺☺
Answer:
(B)
4 +/- 3 sqrt(2) or 4+3sqrt(2) and 4-3sqrt(2)
Step-by-step explanation:
4(c-4)^2=72
4(c-4)(c-4)=72
foil the parenthesis (first, outside, inside, last)
4(c^2 -4c -4c +16)=72
4(c^2-8c+16)=72
divide each side by 4
c^2-8c+16=18
subtract 18 from both sides
c^2-8c-2
use quadratic formula
((-b +/- sqrt((-b^2)-4ac)))/2a
((-(-8)+/-sqrt((-8)^2-4(1)(-2)))/2(1))
(8+/-sqrt(64-(-8)))/2
(8+/-sqrt(64+8))/2
(8+/-sqrt(72))/2
(8+/-sqrt(36 * 2))/2
(8+/-6sqrt(2))/2
4+/-3sqrt(2)
or 4+3sqrt(2) and 4-3sqrt(2)
