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3 years ago

What is the value of x? In a equation

Mathematics

2 answers:

ivann1987 [24]3 years ago

5 0

It's determined by the information given to you in a equation.

kvasek [131]3 years ago

4 0

It could be any number

You might be interested in

Show that if X is a geometric random variable with parameter p, then

Lubov Fominskaja [6]

Answer:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

In order to find the expected value E(1/X) we need to find this sum:

$E(X)=\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}$

Lets consider the following series:

$\sum_{k=1}^{\infty} b^{k-1}$

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

$\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}$ (a)

On the last step we assume that $0\leq r\leq b$ and $\sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}$ , then the integral on the left part of equation (a) would be 1. And we have:

$\int_{0}^b \frac{1}{1-r}dr=-ln(1-b)$

And for the next step we have:

$\sum_{k=1}^{\infty} \frac{b^{k-1}}{k}=\frac{1}{b}\sum_{k=1}^{\infty}\frac{b^k}{k}=-\frac{ln(1-b)}{b}$

And with this we have the requiered proof.

And since $b=1-p$ we have that:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

4 0

3 years ago

In year, 2004, I put $20.00 into an account to save. This account annual interest fee is 0.002%. However, every 10th year the in

olchik [2.2K]

9514 1404 393

Answer:

$20.01

Step-by-step explanation:

In 2004–2012, the interest rate is 0.002%. In 2013, it is 0.004%. In 2014–2021, the interest rate is 0.002%. That is, in the 18 years between 2004 and 2021 (inclusive), the interest rate is 0.002% for 17 of them. The effective account multiplier is ...

(1.00002^17)(1.00004^1) = 1.00038006801

Then the account balance is ...

$20 × 1.00038006801 ≈ $20.01

_____

Additional comment

The annual interest earned on $20.00 is $0.0004. If the account balance is rounded to the nearest cent annually, at the end of the 18 years, the balance will still be $20.00. Not enough interest is earned in one year to increase the balance above $20. At the end of the 18 years, the amount of interest earned is 0.76¢ (a fraction of a penny) only if there is no rounding in intervening years.

7 0

2 years ago

3. Find the lengths of d d 15 7 6 10

siniylev [52]

Answer:

Step-by-step explanation:

As you can see on the side it says 15 and that is the length of the structure and it would be the same all around

4 0

3 years ago

2(c+1)=10 HELP PLSSSSSSSS

Nikolay [14]

Answer:

c=4

Will venus1234 delete the c4?

Step-by-step explanation:

You simplify by distributive property

2c+2=10

Then you can use subtraction property of equality to subtract 2 from both sides to get

2c=8

Then do division property of equality to get the unit rate of c.

You end up with

c=4

Hope this helps!

5 0

3 years ago

Read 2 more answers

PLEASE HELP I WILL MARK U BRAINLIEST!!!! Solve the equation using the zero-product property. Show your work

bazaltina [42]

The answer to the equation is infinitely many solutions

5 0

2 years ago

Read 2 more answers