Please answer see the image please answer correctly, please

Which is the best estimate for the area of the figure above?

nekit [7.7K]

Answer:

So I'd say 20in^2 or 22in^2.

Step-by-step explanation:

I decided to make it into a full pentagon shape to just estimate.

So a pentagons sides are all equal so I counted the amount in boxes on the sides of the regular shape and most of them would be 3.5 if you changed the shape into a pentagon.

And I got:

--> 21.076

5 0

4 years ago

Read 2 more answers

Given the list of terms 1/3, 1, 5/3, 7/3,.... Find the 15th and −16th term.

qwelly [4]

Answer:

15th term =29/3

16th term = 31/3

Step-by-step explanation:

Given an arithmetic sequence with the first term a1 and the common difference d , the nth (or general) term is given by an=a1+(n−1)d .

First we find the 15th term

n=15

a1=1/3

d=1 - 1/3 = 2/3

Solution

1/3+(15-1)2/3

1/3+28/3

(1+28)/3

29/3

Lets find the 16th term

1/3+(16-1)2/3

1/3+30/3

(1+30)/3

31/3

8 0

4 years ago

I xyzdS trong đó S là phần mặt 2 2 z x y nằm giữa hai mặt phẳng z = 0 và z = 1

Anni [7]

Step-by-step explanation:

ewtjsgmsgmgdmgqrhwtjwthwtj

$= . { {y1 {11.1 \times 3 { { {?}^{?} }^{?} }^{?} }^{?} }^{2} }^{2}$

vadbstjtwjsgjdgndymarhedvdhstjwtktwdgharjqrjwrjgjtkstjtsjafbsfnafhafbsfhtshqwdgjwjdjdnnxnxifjnrnthrwhst

$22 {y)bvzv \cot( \beta log( \sec( log( \cot( \sec( \beta \alpha \pi \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( log(?) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) \times \frac{?}{?} }^{2}$

hfzbcEdfgaywjshhsbxbxbxb. seznnxndndnndnxnbxhxududhbdxhhbxhjxjdbnzjsnsnnznzidnxnsbnzjxldkdjdnbx

4 0

3 years ago

23 degrees 20’48 is the same as _degrees.

allochka39001 [22]

Answer:

$\large\boxed{23^o20'48''=\left(23\dfrac{26}{75}\right)^o}$

Step-by-step explanation:

$\text{We know:}\\\\1^o=60'\to1'=\left(\dfrac{1}{60}\right)^o\\\\1'=60''\to1^o=(60)(60'')=3600''\to1''=\left(\dfrac{1}{3600}\right)^o\\\\23^o20'48''\\\\20'=\left(\dfrac{20}{60}\right)^o=\left(\dfrac{1}{3}\right)^o\\\\48''=\left(\dfrac{48}{3600}\right)^o=\left(\dfrac{1}{75}\right)^o\\\\\text{Therefore}\\\\23^o20'48''=23^o+20'+48''=23^o+\left(\dfrac{1}{3}\right)^o+\left(\dfrac{1}{75}\right)^o\\\\=\left(23+\dfrac{1\cdot25}{3\cdot75}+\dfrac{1}{75}\right)^o=\left(23+\dfrac{25}{75}+\dfrac{1}{75}\right)^o=\left(23\dfrac{26}{75}\right)^o$

4 0

4 years ago

When you have coordinates of two points A(1, 2) and B(2,6) slope is:

bearhunter [10]

Answer: 4

Step-by-step explanation:

4 0

2 years ago