Let
x-------> the number of dinner
y-------> the number of lunch
we know that
-------> equation A
------> equation B
Substitute equation B in equation A
![8[y]+5y \leq 42](https://tex.z-dn.net/?f=8%5By%5D%2B5y%20%5Cleq%2042)



so
the greatest number of lunch is 

Hence
the greatest number of dinner is 
therefore
the greatest number of meals is

<u>the answer is</u>


Step-by-step explanation:


Multiply Equation no (1) with 2 and Equation no (2) with 7.







Substitute the value of "y" in Equation no (1)







Answer:
................................................
Step-by-step explanation:
50 + .4x = 70 + .3x
.4x = .3x + 20
.1x = 20
x = 200
Let x be the number of miles.
They have to drive 200 miles.
Answer:
an estimate would be 2000/4 so it would be 500
Step-by-step explanation:
hope this helped <3