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Lina20 [59]
3 years ago
12

Solve . -2 (11 - 4j) = 14 (Solve for J)

Mathematics
1 answer:
Tpy6a [65]3 years ago
7 0

Answer:

4.5

Step-by-step explanation:

-22 +8j = 14

8j = 14 + 22

8j = 36

j = 4.5

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A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 623 babies bo
Margaret [11]

Answer:

The estimation for the number of newborns who weighed between 1724 grams and 5172 grams is 595.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 3448, \sigma = 862

Proportion of newborns who weighed between 1724 grams and 5172 grams.

This is the pvalue of Z when X = 5172 subtracted by the pvalue of Z when X = 1724. So

X = 5172

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{5172 - 3448}{862}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 1724

Z = \frac{X - \mu}{s}

Z = \frac{1724 - 3448}{862}

Z = -2

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

Estimate the number of newborns who weighed between 1724 grams and 5172 grams.

0.9544 out of 623 babies. SO

0.9544*623 = 595

The estimation for the number of newborns who weighed between 1724 grams and 5172 grams is 595.

5 0
3 years ago
Circle A has an area of 500 in.². The diameter of the circle B is three times the diameter of Circle A. Estimate the area of cir
iren2701 [21]
R^2π=500in^2
r^2=500 in^2/π
r=(500 in^2/π)^(1/2)= 12.62 in
plug it in:
db=3da=3(2(12.62))= 75.69
r of b = 75.69/2=37.85in
A of b = (37.85in)^2π = 8.22 in^2



7 0
3 years ago
Neil drives at an average speed of 60 miles/hour to reach his destination 480 miles away. On the way back, he decides to increas
daser333 [38]

Answer:

  480/(x+60) ≤ 7

Step-by-step explanation:

We can use the relations ...

  time = distance/speed

  distance = speed×time

  speed = distance/time

to write the required inequality any of several ways.

Since the problem is posed in terms of time (7 hours) and an increase in speed (x), we can write the time inequality as ...

  480/(60+x) ≤ 7

Multiplying this by the denominator gives us a distance inequality:

  7(60+x) ≥ 480 . . . . . . at his desired speed, Neil will go no less than 480 miles in 7 hours

Or, we can write an inequality for the increase in speed directly:

  480/7 -60 ≤ x . . . . . . x is at least the difference between the speed of 480 miles in 7 hours and the speed of 60 miles per hour

___

Any of the above inequalities will give the desired value of x.

4 0
3 years ago
Which of the following reasons can be used to justify statement #4 in the proof?
8_murik_8 [283]

Answer:

SSS postulate because three sides of a triangle are are congruent

7 0
3 years ago
Read 2 more answers
I need some help with this triangle question...
sweet [91]
Which one dear.....please attach it
6 0
3 years ago
Read 2 more answers
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