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Komok [63]
3 years ago
5

Please helppp!! I’d appreciate it so much

Mathematics
1 answer:
Viefleur [7K]3 years ago
5 0

Answer:

Step-by-step explanation:

Types of angles: Vertical angles

Key Information: The position of the given

Equation: 2x+25=50

Solution: 12.5

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25°<br> У<br> x 120°<br> y = [ ? ]<br> Enter
Alex
95 degrees

you do 180-120 and get 60 and then add 60 and 25 together and that is 85. then u do 180-85 and get 95
5 0
2 years ago
Read 2 more answers
I need help asap !! i’ll make brainliest !! 25 points
valentinak56 [21]

Answer:

I believe it is the second answer;

F(x)= (1/2)(2)^x

Step-by-step explanation:

1. the initial value is 0.5, so the first number will have to be 1/2, and it is increasing so the value of <em>b</em> must be above 1.

2. Through process of elimination, you can determine that the second equation matches the graph.

I hoped this helped! Please comment if you have any questions :)

5 0
2 years ago
PLEASE HELP ASAP!!!!!<br><br> Rewrite the expression 20x + 25 as the product of two factors.
GaryK [48]

Answer:

<em>5 (4 x + 5)</em>

That is the answer

5 is a factor if 20 and 25 and 4x + 5 cannot be furthor be simplified.

5 0
2 years ago
The ratio of the measures of the three angle in a triangle is 15:8:13. Find the measure of the three angles.
Angelina_Jolie [31]

Answer:

a=15x; b=8x; c=13x

180°=a+b+c=15x+8x+13x=36x

=> x=180÷36=5

=> a=15×5=75°; b=8×5=40°; c=13×5=65°

6 0
3 years ago
Which interval contains a local minimum for the graphed function?
DochEvi [55]

Answer : Option D is correct i.e [2.5,4]

Explanation :

Suppose our function is f(x)

then the value of f(x) is minimum where

it reaches -0.44 and 3 with two different intervals .

As we know that for finding the local minimum ,

the criteria is that  f'(x)=0 .

So, here

f'(-0.44)=0 and

f'(3)=0

both are the local minimum point for the function f(x)

but -0.44 is the global minimum point .

In our case for [2.5,4] is the required interval where f(x) reaches its  local minimum.

4 0
3 years ago
Read 2 more answers
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