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Svet_ta [14]
3 years ago
10

The access code for a​ car's security system consists of sixsix digits. the first digit cannot be zerozero and the last digit mu

st be oddodd. how many different codes are​ available?
Mathematics
2 answers:
Rudiy273 years ago
4 0
54 different codes should be right
Iteru [2.4K]3 years ago
4 0

You didn't say anything so I have to assume that other than the two conditions mentioned for the fist and last digit, all numbers 0-9 are permissible.

1st digit cannot be a 5. Therefore there are 9 possibilities
digits 2-5 can be any digit. There are 10 possibilities for each. There are 4 digits involved, so there are 104 possibilities.
Finally the last, 6th digit must be odd. Therefore there are 5 possibilities.

The number of different possible codes is
9 x 104 x 5 = 45 x 104 = 450,000
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Step-by-step explanation:

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