Answer: here are a few ordered pairs
1. (0,-4)
2.(8,0)
3.(16,4)
Answer:
We accept H₀ we don´t have enough evidence to support that the mean thickness is greater than 41 mm
Step-by-step explanation:
Sample Information:
Results:
41.8
40.9
42.1
41.2
40.5
41.1
42.6
40.6
From the table we get:
sample mean : x = 41.35
sample standard deviation s = 0.698
Hypothesis Test:
Null Hypothesis H₀ x = 41
Alternative Hypothesis Hₐ x > 41
The test is a one-tail test
If significance level is 0.01 and n = 8 we need to use t-student distribution
From t-table α = 0.01 and degree of freedom df = n - 1 df = 8 - 1
df = 7 t(c) = 2.998
To calculate t(s) = ( x - 41 ) / s/√n
t(s) = ( 41.35 - 41 ) / 0.698/√8
t(s) = 0.35 * 2.83/ 0.698
t(s) = 1.419
Comparing t(s) and t(c)
t(s) < t(c)
t(s) is in the acceptance region we accept H₀
GCF(3, 24, 27) = 3
Steps:
Prime factorization of the numbers:
3 = 3
24 = 2 × 2 × 2 × 3
27 = 3 × 3 × 3
GCF(3, 24, 27)
= 3
I think the answer is:
Rectangle: X X O X X
Rhombus: X X X X O
Square: X X X X X
I hope you got a good grade!!!
Answer:
Option A.
Step-by-step explanation:
The given sequence is
24, 30, 36, 42, 48, ...
It is an AP. Here,
First term = 24
Common difference = 30-24 = 6
The given explicit formula for nth term is
where, 
is first term, d is common difference.
Substitute 
in the above formula.
The 500th term of the sequence is 3018.
Therefore, the correct option is A.
