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frez [133]
2 years ago
12

9° TERMINO DE 7.10.13​

Mathematics
2 answers:
andrew-mc [135]2 years ago
3 0

Answer:

djkdjdjfifkflkfkfuiririrkrkkr kfkrkrkrlrlrlrlrlrlfkkrkfllrkrkrkkrkfkkfkkrkrkrkkrkrkkr krkrkkkkrkfkkkkfkrkkfkfkfkkf ir rkkfikriffiriifi

ycow [4]2 years ago
3 0

Answer:

Evaluate

18 ER TM×2,130

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Whitepunk [10]
35.98 million miles from the sun
3 0
3 years ago
I am stuck on this question of my maths test.
V125BC [204]

Answer:

angle y

58 + 38 + y = 180 (angle sum property)

96 + y = 180

y = 180 - 96

y = 84

angle x

x = 29 (58/2)

(angle subtended by an arc at centre is double the arc at any point on remaining part of centre)

the values of x = 29 and y = 84

6 0
3 years ago
How do i do 3 part a ?
WINSTONCH [101]


In general the binomial expansion is


(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0


So in our case, because we want ascending powers of x we'll write,


(-3x + 1)^{11} =  {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9  + {11 \choose 3 } (-3x)^3 1^8 + ...


We need to calculate the binomial coefficients:


{11 \choose 0}  = 1


{11 \choose 1}  = 11


{11 \choose 2}  = \dfrac{11 \times 10}{2} = 55


{11 \choose 3}  = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165


(-3x+1)^{11} =  1 (-3x)^0 1^{11}  + 11(-3x)^{1} 1^{10}  + 55 (-3x)^2 1^{9}  + 165 (-3x)^3 1^8 + ...


(1-3x)^{11} =  1 -33 x + 495 3x^2 - 4455 x^3+ ...



6 0
3 years ago
Need help with this question. Thank you!
Paul [167]

Answer:

61.2

Step-by-step explanation:

Distribute the figure into three shapes. Triangle, and two rectangles.

Find the area.

8 0
3 years ago
Read 2 more answers
Help asap
Nikolay [14]
First, you would create an equation for this problem. 
\frac{18}{15}= \frac{x}{100}

Next, you would cross multiply. 
15x = 1,800

Now, you would isolate the x. To do this, you would divide both sides by 15. 
x = 120

It is a 120% increase. 

I hope this helps!
7 0
3 years ago
Read 2 more answers
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