For this case we first define the variable:
x = number of terms.
The equation that models the problem is:
f (x) = 3.4 - 0.6x
We have then that the first four terms are:
x = 1
f (1) = 3.4 - 0.6 (1) = 3.4 - 0.6 = 2.8
x = 2
f (2) = 3.4 - 0.6 (2) = 3.4 - 1.2 = 2.2
x = 3
f (3) = 3.4 - 0.6 (3) = 3.4 - 1.8 = 1.6
x = 4
f (4) = 3.4 - 0.6 (4) = 3.4 - 2.4 = 1
Answer:
The rule for the sequence is:
f (x) = 3.4 - 0.6x
option 1
Answer:
90
Step-by-step explanation:
10+67
7586+65
576845=8757685
2+88=90
Answer:
Answer is last alternative
scale factor (2)
Answer:
- 15, - 16
Step-by-step explanation:
-15 + (-16) = - 15 - 16 = - 31
Answer:
E. 396/538
Step-by-step explanation:
The probability that the senior selected will not be from High School B given that the senior did not answer colege:
First, what's the probability of not having answered college? This will be out denominator.
P(not choosing college) = 244 + 106 + 188 = 538
Next, what's the probability that a senior in that category is not from HS B? Well, add the probabilities that the senior is in HS A or C:
P(senior is in HS A or C and answered not college) = 49 + 99 + 63 + 83 + 31 + 71 = 396
<u>Our answer is E. 396/538.</u>
