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2 years ago

Please help with HW. I will give brainliest.

Mathematics

1 answer:

sammy [17]2 years ago

5 0

Answer:

for page 1, the answer is y = x + 1

for page 2, the answer is linear

Step-by-step explanation:

Why is it y = x + 1?

It is y = x + 1 because if you look at the steps, all of them are reasonable for having a multiplication equation. Step 1 has a equation of 1 x 1, step 2 has an equation of 2 x 2, and step 3 has an equation of 3 x 3. So the relationship would be adding +1 to every step and count up from 1 - 3.

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Why is it linear?

It's linear cause the relationship between x and y is called a linear relationship because the points so plotted all lie on a single straight line.

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Help please<br> I’m trying to find value of x and y. i need to write out the problem

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2 years ago

A rectangle with an area of 5/8 ft² is dilated by a factor of 8. What is the area of the dilated rectangle?

gulaghasi [49]

Answer:

40 ft²

Step-by-step explanation:

Let the length of the original rectangle be L and original Breadth be B

it is given that the original area is 5/8 ft²

i.e.

Original Length x Original Breadth = Original Area, or,

LB = 5/8 ft² ------------------(1)

Given that the dilation factor is 8,

Hence,

New Length = 8L and New Breadth = 8B

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3 years ago

Question 1<br> Re-write this list of numbers in ascending order:<br> 0.9, 0.23, 0.89

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2 years ago

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Simplify (3x-5x)+(5x+1)

Lemur [1.5K]

First do
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3 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

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2 years ago

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