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stich3 [128]
3 years ago
10

Helpppppppppp plz..............

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Answer:

8miles

Step-by-step explanation:

velocity= 6/(45/60)=8miles/h

distance = 8miles in 1 hour

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A new dental bondlng agent. When bonding teeth, orthodontists must maintain a dry field. A new bonding adhesive(called "Smartbon
Gemiola [76]

Answer:

(a) <em>H</em>₀: <em>μ ≥ 5.70 </em><em>vs. </em><em>Hₐ</em>:<em>μ < 5.70</em>

(b) The rejection region is (<em>t₀.₀₁,₉</em> <em>≤ -2.821</em>).

(c) The value of the test statistic is -4.33.

(d) The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

Step-by-step explanation:

A hypothesis test should be conducted to determine that the if the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(a)

The hypothesis is:

<em>H</em>₀: The true mean breaking strength of the new bonding adhesive is not less than 5.70 Mpa, i.e. <em>μ ≥ 5.70</em><em>.</em>

<em>Hₐ</em>: The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa, i.e. <em>μ < 5.70</em><em>.</em>

(b)

The alternate hypothesis indicates that the hypothesis test is left-tailed.

The rejection region for the left tailed test will be towards the lower tail of the t<em>-</em>distribution curve.

The significance level of the test is: <em>α</em> = 0.01.

The critical value is:

t_{\alpha ,(n-1)}=t_{0.01,(10-1)}=t_{0.01,9}

Use the <em>t-</em>table for the critical value.

t_{\alpha ,(n-1)}=t_{0.01,9}=-2.821

Since rejection region is in the lower tail the critical value will be negative.

Thus, the rejection region is (<em>t₀.₀₁,₉</em> <em>≤ -2.821</em>).

(c)

The test statistic value is:

t=\frac{\bar x-\mu}{s/\sqrt{n}}

Given:

\bar x=5.07\\s=0.46\\n=10\\\mu=5.70

Compute the value of the <em>t</em>-statistic as follows:

t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{5.07-5.70}{0.46/\sqrt{10}} =-4.33

The value of the test statistic is -4.33.

(d)

The value of the test is less than the critical value.

t=-4.33

This implies that the test statistic lies in the rejection region.

Hence the null hypothesis will be rejected at 1% significance level.

<u>Conclusion:</u>

As the null hypothesis is rejected it can be concluded that the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(e)

The conditions required for the <em>t-</em>test for single mean to be valid is:

  • The data should be continuous.
  • The parent population should be normally distributed.
  • The sample should be randomly selected.

5 0
3 years ago
It took team rise over run 1 2/3 hours to hike 4 2/3 miles. What is their average speed in miles per hour?
pogonyaev

To find their average miles per hour we can divide the total miles by the hour used:

4 2/3 ÷ 1 2/3

=4x3+2/3 ÷ 1x3+2/3

=14/3 ÷ 5/3

In division, when we switch the place of numerator and denominator, we can change it to multiplication which makes the calculation easier as we can factorize the numbers.

=14/3 x 3/5

Factorize 3 in both amounts:

=14/1 x 5/1

=14/5

=2.8 miles/hour

Therefore their average speed is 2.8 miles/hour.

Hope it helps!

8 0
2 years ago
PLEASEEEEE help I me I will give you BRAINLEST!!!
Tasya [4]

Answer:

(-2,-2)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
An animal shelter spends $5.00 per day to care for each bird and $7.50 per day to care for each cat. Jayden noticed that the she
Vilka [71]

Answer:

   24 birds

Step-by-step explanation:

Let b represent the number of birds at the shelter on Wednesday. Then the cost of care for the 41 animals is ...

  5b +7.5(41 -b) = 247.50

  -2.5b +307.50 = 247.50 . . . . . simplify

  -2.5b = -60 . . . . . . . . . . . . . . . . subtract 307.50

  b = 24 . . . . . . . . . divide by -2.5

The number of birds at the shelter on Wednesday was 24.

7 0
3 years ago
Find the greatest common factor of 15x 2 y 3 and -20x 3 yz.
vekshin1
Multiply the GCF of the numerical part 3 and the GCF of the variable part x^2y to get 
3x^2y. 
7 0
2 years ago
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