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BaLLatris [955]
3 years ago
9

PLEASE HELP AND HURRY

Mathematics
1 answer:
kogti [31]3 years ago
6 0

Here the given expression is

y =(\frac{3}{4})^x

We need to find the value of y when x =3 . So we substitute the value of x in the given expression.

y =(\frac{3}{4})^3 = \frac{27}{64} =0.4

So when x=3, y=0.4 and that's the required answer.

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r=\frac{n\Sigma xy-\Sigma x\Sigma y}{\sqrt{(n\Sigma x^2-(\Sigma x)^2)(n\Sigma y^2-(\Sigma y)^2)}}

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\begin{gathered} \Sigma xy=\text{ sum of the column of xy} \\ \Sigma x=\text{ sum of the column x} \\ \Sigma y=\text{ sum of the column y} \\ \Sigma x^2=\text{ sum of the column x\textasciicircum2} \\ \Sigma y^2=\text{ sum of the column y\textasciicircum2} \\ n=\text{ number of rows} \end{gathered}

Now we substitute the values, we get:

r=\frac{\left(6)(70.56)-(25.2)(16.4\right)}{\sqrt{((6)(107.12)-(25.2)^2)((6)(47.82)-(16.4)^2)}}

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r=0.858

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I believe ur converting tons to pounds right?

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