There is 9 chocolate cookies, so the probability of choosing chocolate is
. We then simplify to get
, or 0.3.
Answer:
70.45%
Step-by-step explanation:
The markup is $75 -44 = $31. As a percentage of the wholesale price, that is ...
$31/$44 × 100% ≈ 70.45%
Answer:

Step-by-step explanation:
<u>Let's derive a formula</u> :
⇒ Area (triangle) × 3 = Area (square)
⇒ 1/2(bh) × 3 = a²
∴ But a = h (shown in diagram)
⇒ 3/2(bh) = h²
⇒ <u>h = 3b/2</u>
<u>Now, taking tan θ</u> :
⇒ tan θ = b/h
⇒ tan θ = b/(3b/2)
⇒ tan θ = 2b/3b
⇒ tan θ = 2/3
Answer:
D = 59t
P = 42t
5 hours after noon, darmian is 17 miles closer to the stadium than paisley
Step-by-step explanation:
At noon, Damian is 383 miles away from the stadium and paisley is 315 miles away from the stadium.
Now, we are told that damians speed is 59 mph while paisley's speed is 42 mph.
At t hours after noon, their distance covered will be;
Damian; D = 59t
Paisley; P = 42t
This is because distance = speed × time
Now, 5 hours after noon, their respective distance covered will be;
D(5) = 59 × 5 = 295 miles
P(5) = 42 × 5 = 210 miles
This means that;
distance of Damian from the stadium is; 383 - 295 = 88 miles
Distance of paisley from the stadium is;
315 - 210 = 105 miles
Difference in their distances to the stadium = 105 - 88 = 17 miles
Thus, 5 hours after noon, darmian is 17 miles closer to the stadium than paisley
Probaility in general is defined as the ratio of positive outcomes over the total number of outcomes.
In the first example, the total outcomes are 16; let us count the positive ones. There are 8 even numbers from 1-16. The prime numbers are 2,3,5,7,11,13. Out of those, only 5 are odd. Hence, in total there are 13 positive outcomes. Thus, the probability is 13/16=81.25%
Let's restrict the problem to the students that studied for the exam; the proportion is 0.57 of the total students. 0.52 of the total students studied and saw an increase in their exam. Hence, the probability that a student who studied saw an increse is 0.52/0.57 (here a positive outcome is the proportion that saw an increase and the total outcomes are all the students that studied). 0.52/0.57=91.22%