1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
monitta
2 years ago
11

I need help with this, please answer

Mathematics
1 answer:
Sholpan [36]2 years ago
8 0

Answer:

3 and 13 are supplementary angles.

8 and 10 are vertically opposite angles.

11 and 15 are co - interior angles.

8 and 16 are vertically opposite angles.

1 and 6 are alternating angles.

6 and 10 are supplementary angles.

14 and 15 are supplementary angles.

You might be interested in
Identify the factors of x2 + 25y2. ...?
Sveta_85 [38]
Is the equation like this? x^2 + 25y^2?
If the equation is like that, the answer would be (x-5y)^2 or (x-5y)(x-5y).
how did I get this? Just divide the factors or the get the square root of 25y^2 and it would be 5y. Then just try if it is positive or negative. In this case, it is negative because there is no factor w/ no exponential form. I hopemy answer helped you.
4 0
3 years ago
∠A and \angle B∠B are supplementary angles. If m\angle A=(x-16)^{\circ}∠A=(x−16) ∘ and m\angle B=(3x+28)^{\circ}∠B=(3x+28) ∘ , t
GalinKa [24]

Answer:

  ∠A = 26°

Step-by-step explanation:

Supplementary angles total 180°.

  ∠A +∠B = 180°

  (x -16)° +(3x +28)° = 180°

  4x° + 12° = 180°

  x° +3° = 45°

  x° = 42°

  ∠A = (x -16)° = 42° -16°

  ∠A = 26°

3 0
3 years ago
What is the surface area of the figure shown? Plz answer asap
Luba_88 [7]

Answer:

264\ cm^{2}

Step-by-step explanation:

we know that

The surface area of the figure is equal to the lateral face of the triangular pyramid plus the lateral face of the rectangular prism plus the area of the base of the rectangular prism

step 1

Find the lateral face of the triangular prism

The lateral area is equal to the area of its four lateral triangular faces

LA=4(\frac{1}{2}(6)(7))=84\ cm^{2}

step 2

Find the lateral area of the rectangular prism

The lateral area is equal to the perimeter of the base multiplied by the height

LA=(4)(6)(6)=144\ cm^{2}

step 3

Find the area of the base of the rectangular prism

B=(6)(6)=36\ cm^{2}

step 4

Find the surface area

84\ cm^{2}+144\ cm^{2}+36\ cm^{2}=264\ cm^{2}

3 0
3 years ago
Margaret is saving money for her summer vacation. She calculates that her starting amount is 0.4% of the total amount she wants
garri49 [273]

0.4% can be written as 0.004 in decimal.

Step-by-step explanation:

Let the total amount she wants to save be 'a'

Starting amount = 0.4% of the total amount

= 0.4% of a

= (0.4/100) a

0.4% = 0.4/100

= 0.004

0.4% can be written as 0.004 in decimal.

5 0
3 years ago
Jeremy used a total of 16 sticks to support his vegetables. The sticks were 55cm and 75cm long and the sum of their lengths was
svetoff [14.1K]
9 longer sticks were used.
This is how i get it.
1. change m to cm, 1m =100cm
2. add both together, divide by 16 =8.125. Which means 1 of the stick should more than 8, and 1 of the other stick should be less than 8
3. substitute the equation
4.(55 x 7)+(75 x 9) =1060

5 0
3 years ago
Other questions:
  • Can you please help me with this one please
    5·2 answers
  • Help please with 24 ....
    10·1 answer
  • The chef at a school cafeteria asked 100 male and 100 female students
    14·1 answer
  • For each part, use your knowledge of the definition of radians and the definitions of sine, cosine, and
    5·1 answer
  • What is the rule for this pattern
    5·1 answer
  • Is (-1,7) a solution for the system of linear equations below? x + 2y = 13 and 3x - y
    8·1 answer
  • What’s the answer for 6?
    12·1 answer
  • Which value is a solution for the equation tan x/2 = -1?
    7·2 answers
  • I have more question just don't get it wronge
    6·2 answers
  • I know this is easy and i should know but im actually stumped on this one
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!