Not a lot of details, but the answer is:
b = how many miles is in the bike a thon
b x 1/10 = x
x = how many miles yoshi completer
Answer:
58
Step-by-step explanation:
Let's draw this out (see attachment).
We know that since B lies on AC, we have the points in order from left to right: A, B, C.
AB = 9, which is the left portion. BC = 49, which is the right portion. Then AC is simply the sum:
AC = AB + BC = 9 + 49 = 58
The answer is thus 58.
<em>~ an aesthetics lover</em>
Answer:
(1 
, 2 )
Step-by-step explanation:
Given the 2 equations
7x - y = 7 → (1)
x + 2y = 6 → (2)
Multiplying (1) by 2 and adding to (2) will eliminate the y- term
14x - 2y = 14 → (3)
Add (2) and (3) term by term to eliminate y
15x = 20 ( divide both sides by 15 )
x = 
= 
= 1
Substitute this value of x into either of the 2 equations and solve for y
Substituting in (2)
+ 2y = 6
2y = 6 - = 
( divide both sides by 2 )
y = 
= 2
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
