Answer is in the file below
tinyurl.com/wpazsebu
Answer:
Both the parts of this question require the use of the "Intersecting Secant-Tangent Theorem".
Part A
The definition of the Intersecting Secant-Tangent Theorem is:
"If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment."
This, when applied to our case becomes, "The length of the secant RT, times its external segment, ST, equals the square of the tangent segment TU".
Mathematically, it can be written as:
Part B
It is given that RT = 9 in. and ST = 4 in. Thus, it is definitely possible to find the value of the length TU and it can be found using the Intersecting Secant-Tangent Theorem as:
Thus,
Thus the length of TU=6 inches
Answer:
see below
Step-by-step explanation:
Twice p added to 4 multiplied by p is equal to 20
2. Use rise over run to find it
Looking at x^2 - x - 30, we see that 5*6=30, so we can immediately conclude that <span>x^2 - x - 30 = (x+5)(x-6). check this by multiplication.
</span><span>2m^2 - 2m - 60 can be reduced to 2(m^2 - m - 30), which in turn can be factored as 2(m+5)(m-6). The trick here is to notice how easily "2" can be factored out of the given equation.
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