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3 years ago

What are the zeros of the f(x)=x(x-9)

Mathematics

1 answer:

Vaselesa [24]3 years ago

7 0

X1= 0, X2= 9
I hope this helps!

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3 years ago

29. Find the height of the trapezoid. Use this height to find the area. (A =

harkovskaia [24]

Answer:

<em>The area of the trapezium is 168</em>

Step-by-step explanation:

<u>Area of a Trapezoid</u>

Given a trapezoid of parallel bases b1 and b2, and height h, the area is calculated with the formula:

$\displaystyle A=\frac{b_1+b_2}{2}h$

The trapezoid in the figure has b1=15 and b2=27. We need to find the height. If we focus on triangle BCD, we can calculate the height as the distance EC by using the Pythagora's Theorem:

$10^2=EC^2+BC^2$

The side BC can be found as half the difference of the bases:

$BC=\frac{27-15}{2}=6$

Solving for EC:

$EC^2=10^2-6^2=100-36=64$

$EC=\sqrt{64}=8$

Now we have the height, calculate the area:

$\displaystyle A=\frac{15+27}{2}*8$

$\displaystyle A=\frac{42}{2}*8$

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5 0

3 years ago

What are the real zeros of the function g(x)=x^3+2x^2-x-2

Gre4nikov [31]

$g(x)=x^3+2x^2-x-2\\\\\text{The zeros:}\\\\g(x)=0\to x^3+2x^2-x-2=0\\\\x^2(x+2)-1(x+2)=0\\\\(x+2)(x^2-1)=0\iff x+2=0\ \vee\ x^2-1=0\\\\x+2=0\ \ \ |-2\\x=-2\\\\x^2-1=0\ \ \ |+1\\x^2=1\to x=\pm\sqrt{1}\to x=-1\ \vee\ x=1\\\\\text{Answer:}\ x=-2\ or\ x=-1\ or\ x=1$

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3 years ago