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Stolb23 [73]
3 years ago
8

The function y=f(x) is graphed below. Plot a line segment connecting the the points on f where x=5 and x=7. Use the line segment

to determine the average rate of change of the function f(x) on the interval

Mathematics
1 answer:
aksik [14]3 years ago
8 0

Answer: average y = -8 average y =2

ARC : -4

Step-by-step explanation:

You might be interested in
Denzel has a new puppy that weighs 12 pounds. The vet says that the puppy is now at about 20% of its adult weight. What will be
olchik [2.2K]

Answer:

60 pounds

Step-by-step explanation:

To find the adult weight, multiply 12 by 5.

Since 12 pounds is 20% of the adult weight, 100% of the adult weight would be 12 times 5.

12(5)

= 60

So, the adult weight of the puppy will be 60 pounds

7 0
3 years ago
PLEASE HELP ME I BEG I WILL GIVE BRAINLIEST
ohaa [14]

Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

7 0
3 years ago
38b/-19<br><br> please help me
Natasha2012 [34]
You didn't write what to do with the fraction but I think you meant to ask to simplify it:
38b/-19
Multiply - 19 from top and bottom :
-2b
7 0
3 years ago
A person plans to invest a total of $3500 in one bank account at 2.2% annual interest and another bank account at 17% annual int
jeka57 [31]

Answer:

$435.3

Step-by-step explanation:

Assuming simple interest

Interest, I=Pi/100 where P is principal amount and i is rate of interest in percentage

For $3500, the interest will be 3500*2.2/100=$77

From total target of $151, the person is less 151-77=$74

Taking x as principal and rate of interest as 17% then

0.17x=74

X=74/0.17=$435.2941176470

Rounded off as $435.3

6 0
3 years ago
I need both of these questions answered I also HATE links so please don’t put any down(;´༎ຶٹ༎ຶ`)
Mademuasel [1]
The first one is 12.5%

the second one is .18
3 0
3 years ago
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