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allsm [11]
3 years ago
7

The distance between two cities is 325.65 km. About how far apart are they to the nearest kilometer?

Mathematics
2 answers:
Brums [2.3K]3 years ago
8 0
The two cities are 326 kilometers away
Bogdan [553]3 years ago
6 0
5 and up, raise it up
4 and below, keep it low!
Raise it up to 326km
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3 years ago
Is the set of numbers one 1,5,25 and 125 a geometric sequence
Strike441 [17]
Short answer: Yes.
Each member of the sequence is multiplied by 5 to get to the next member of the sequence.

Find the general equation.
tn = a*5^(n - 1)

Example
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t4 = 1*5^3
t4 = 125 just as the sequence shows.

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A triangular prism is shown in the diagram.
qaws [65]

Answer:

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Step-by-step explanation:

See attached image.

8 0
3 years ago
PLEASE HELP ME IM STRUGGLING!!!
Kitty [74]

Answer:

The required answer is c=7\sqrt{3}

Therefore the number in green box should be 7.

Step-by-step explanation:

Given:

AB = 7√2

AD = a , BD = b , DC = c , AC = d

∠B = 45°, ∠C = 30°

To Find:

c = ?

Solution:

In Right Angle Triangle ABD Sine identity we have

\sin B = \dfrac{\textrm{side opposite to angle B}}{Hypotenuse}\\

Substituting the values we get

\sin 45 = \dfrac{AD}{AB}= \dfrac{a}{7\sqrt{2}}

\dfrac{1}{\sqrt{2}}= \dfrac{a}{7\sqrt{2}}\\\\\therefore a=7

Now in Triangle ADC Tangent identity we have

\tan C = \dfrac{\textrm{side opposite to angle C}}{\textrm{side adjacent to angle C}}

Substituting the values we get

\tan 30 = \dfrac{AD}{DC}= \dfrac{a}{c}\\\\\dfrac{1}{\sqrt{3}}=\dfrac{7}{c}\\\\\therefore c=7\sqrt{3}

The required answer is c=7\sqrt{3}

8 0
3 years ago
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