WILL MARK BRAINLIEST TIMED HELP!

Can someone please tell me if these are correct?

iragen [17]

Number one is correct and so is two

3 0

3 years ago

Read 2 more answers

This is my my second to <br>last one, thanks for helping me

icang [17]

9514 1404 393

Answer:

$9
Option 4

Step-by-step explanation:

The equations need to match the problem statements. If we let C and S represent the costs of Cherry and Sweet potato pies, respectively, then the revenue from each sale can be expressed as an equation.

1 cherry and 7 sweet potato for $114 ⇒ C +7S = 114

14 sweet potato and 11 cherry for $309 ⇒ 11C +14S = 309

Note that we have used C and S in the second equation in the same order as they appeared in the first equation, even though the problem statement has that order reversed. This facilitates solving the equations using elimination or Cramer's rule.

These equations match Option 4.

__

The cost of a cherry pie can be found by eliminating S from the equations. We can do that by subtracting twice the first equation from the second:

(11C +14S) -2(C +7S) = (309) -2(114)

9C = 81 . . . . . simplify

C = 9 . . . . . . . divide by 9

The cost of each cherry pie is $9.

3 0

3 years ago

What is the area of triangle MOL? 200 square units 250 square units 300 square units 500 square units

In-s [12.5K]

Answer:

300 square units

Step-by-step explanation:

explanation-because i just know

4 0

3 years ago

A store finds that its sales revenue changes at a rate given by S'(t) = −30t2 + 420t dollars per day where t is the number of da

allochka39001 [22]

Answer:

Step-by-step explanation:

Give the rate of change of sales revenue of a store modeled by the equation $S'(t)= -30t^{2} + 420t$ . The Total sales revenue function S(t) can be gotten by integrating the function given as shown;

$\int\limits {S'(t)} \, dt = \int\limits ({-30t^{2}+420t }) \, dt \\S(t) = \frac{-30t^{3} }{3}+\frac{420t^{2} }{2}\\ S(t)= -10t^{3} +210t^{2} \\$

a) The total sales for the first week after the campaign ends (t = 0 to t = 7) is expressed as shown;

$Given\ S(t) = -10t^{3} + 210t^{2}$

$S(0) = -10(0)^{3} + 210(0)^{2}\\S(0) = 0\\S(7) = -10(7)^{3} + 210(7)^{2}\\S(7) = -3430+10,290\\S(7) = 6,860$

Total sales = S(7) - S(0)

= 6,860 - 0

Total sales for the first week = $6,860

b) The total sales for the secondweek after the campaign ends (t = 7 to t = 14) is expressed as shown;

Total sales for the second week = S(14)-S(7)

Given S(7) = 6,860

To get S(14);

$S(14) = -10(14)^{3} + 210(14)^{2}\\S(14) = -27,440+41,160\\S(14) = 13,720$

The total sales for the second week after campaign ends = 13,720 - 6,860

= $6,860

8 0

3 years ago

Last week Rachel power walked 2 3/5 miles per day on each of the seven days during the same week she also jogged 5 3/4 per day o

Korolek [52]

41 and 1/5 miles.

You can get this by multiplying the distances by number of days. Then add the two together.

3 0

3 years ago