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OLEGan [10]
4 years ago
9

Emilia lost $4,000 in personal belongings due to a flood at her apartment complex. Fortunately, she had renter’s insurance with

a $500 deductible. How much would she receive from the insurance company if her maximum coverage was $10,000? $4,000.00 $500.00 $3,500.00 $4,500.00
Mathematics
1 answer:
docker41 [41]4 years ago
3 0
She would receive $3500 maximum.

Since she has $10,000 in coverage, the entire $4000 loss is covered.  However, the insurance company would only pay her the amount after the deductible has been taken:

4000 - 500 = 3500
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Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
Solve for the missing side to the nearest tenth.<br> 16<br> 30<br> X =
Mrrafil [7]

Answer: x=32

Step-by-step explanation:

Because a triangle is 180°, the missing angle in the triangle would be 60°.

Because of the 30°-60°-90° angles theorem, The side opposite 90° is double the side opposite 30°, which means that x=32.

3 0
3 years ago
Which data set does the histogram represent?
MAVERICK [17]

Answer/Step-by-step explanation:

Ok so there is

3, 0-4                  4, 5-9                2, 10-14             1, 15-19       1, 20-24

so you can get rid of the last one saying it has more than 1 number between 20-24.

The 3rd one has to short of numbers for 0-4.

the second one has way to many 0-4's when there should be 3 of them.

therefore your answer is The firstone.

7 0
2 years ago
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Please Help! Question is:
Natasha_Volkova [10]

Answer: D

Step-by-step explanation:

5 0
4 years ago
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The tables show some input and output values:
blsea [12.9K]
The answer is 2.Only B because, functions can't have input values of the same number. Table B has <span>7, 3 & 7,2 which both have 7 as their input value. </span>
5 0
4 years ago
Read 2 more answers
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