Answer:
CH4
Explanation:
In solving this problem, we must remember that one mole of a compound contains Avogadro's number of elementary entities. These elementary entities include atoms, molecules, ions etc. Recall that one mole of a substance is the amount of substance that contains the same number of elementary entities as 12g of carbon-12. The Avogadro's number is 6.02 × 10^23.
Hence we can now say;
If 163 g of the compound contains 6.13 ×10^24 molecules
x g will contain 6.02 × 10^23 molecules
x= 163 × 6.02 × 10^23 / 6.13 × 10^24
x= 981.26 × 10^23/ 6.13 ×10^24
x= 160.1 × 10^-1 g
x= 16.01 g
x= 16 g(approximately)
16 g is the molecular mass of methane hence x must be methane (CH4)
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Answer:
The answer is Ce^4+ (aq) + Mn^2+ (aq) ==> Ce^3+ (aq) + Mn^3+ (aq)
Explanation:
The reaction is first order with respect to Ce^4+ and first order with respect to Mn^2+ below.
Ce^4+ (aq) + Mn^2+ (aq) ==> Ce^3+ (aq) + Mn^3+ (aq)
The rate calculation,
Ce^4+ (aq) + Mn^2+ (aq) ==> Ce^3+ (aq) + Mn^3+ (aq)
This is the catalyzed reaction.
(NH4)3PO4
=
Nitrogen = 3
Hydrogen = 4x3 (12)
Phosphorus = 1
Oxygen = 4
3+12+1+4=20
the answer is there are 20 atoms
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