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aalyn [17]
3 years ago
5

Turn this improper fraction in mixed numbers.23/7​

Mathematics
1 answer:
Pavel [41]3 years ago
3 0

Answer:

3  2 /7

Step-by-step explanation:

Divide using long division. The whole number portion will be the number of times the denominator of the original fraction divides evenly into the numerator of the original fraction, and the fraction portion of the mixed number will be the remainder of the original fraction division over the denominator of the original fraction.

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You are collecting a sample of 60 data points from a population that you know to follow an exponential distribution. It is not a
11111nata11111 [884]

Answer:

For the exponential distribution:

\mu = \frac{1}{\lambda}

\sigma^2 = \frac{1}{\lambda^2}

We know that the exponential distribution is skewed but the sample mean for this case using a sample size of 60 would be approximately normal, so then we can conclude that if we have a sample size like this one and an exponential distribution we can approximate the sample mean to the noemal distribution and indeed use the Central Limit theorem.

\bar X \sim N(\mu_{\bar X} , \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = \bar X

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}

Step-by-step explanation:

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

For this case we have a large sample size n =60 >30

The exponential distribution is the probability distribution that describes the time between events in a Poisson process.

For the exponential distribution:

\mu = \frac{1}{\lambda}

\sigma^2 = \frac{1}{\lambda^2}

We know that the exponential distribution is skewed but the sample mean for this case using a sample size of 60 would be approximately normal, so then we can conclude that if we have a sample size like this one and an exponential distribution we can approximate the sample mean to the noemal distribution and indeed use the Central Limit theorem.

\bar X \sim N(\mu_{\bar X} , \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = \bar X

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}

5 0
4 years ago
Can someone help me, please?
Nadusha1986 [10]
It’s the second one
5 0
3 years ago
Find the slope of the line that contains the points:
Semenov [28]

Answer:

slope is 1

Step-by-step explanation:

5-3/-4--6 = 2/2 = 1

5 0
3 years ago
Read 2 more answers
Solve an equation to determine the unknown quantity.
Montano1993 [528]
-75 times 5 = 30
Add 75 to 30 =105
105 divided by 5= 21
Kakapo should be 21 inches. Hope this helps sorry if wrong!
4 0
3 years ago
Solve the inequality.<br> -3.25y &lt;-61.75
Inessa [10]

Step-by-step explanation:

-3.25y < -61.75

<u>-3.25y</u><u> </u>< <u>-61.75</u><u> </u>

-3.25. -3.25

whenever an inequality is divided by a negative number the sign changes, so if the sign of the inequality is greater than( > ) it becomes less than( < ) or the other way around. In this case the <em>less</em><em> </em><em>than</em><em> </em>will be <em>greater</em><em> </em><em>than</em><em>.</em>

y > 19 , S.S= [ 20,21,22,23.....]

7 0
3 years ago
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