energy is always transformed from one form to another
energy is not created nor destroyed
so when a car starts moving the chemical potential energy of the car is converted to kinetic energy
kinetic energy is the energy that moving objects possess
kinetic energy formula is as follows
Kinetic energy = 1/2 mv²
where m - mass
v - velocity
substituting these values
K.E = 1/2 x 1350 kg x (12 m/s)²
= 1/2 x 1350 x 144 = 97200 J
the kinetic energy of the car is 97.2 kJ
Answer:
Each yard is 150 meters wide and 200 meters tall.
The overall area is 300 meters wide by 200 meters tall.
Step-by-step explanation:
Let's say each yard has a width w and a height h. And let's say the part of the fence that divides them is parallel to the height. The total amount of fencing is therefore:
1200 = 4w + 3h
The total enclosed area is:
A = 2wh
Start by solving for w in the first equation:
1200 − 3h = 4w
w = 300 − 0.75h
Substitute into the second equation:
A = 2 (300 − 0.75h) h
A = 600h − 1.5h²
Take derivative and set to 0:
dA/dh = 600 − 3h
0 = 600 − 3h
h = 200
Solve for w:
w = 300 − 0.75h
w = 150
So each yard is 150 meters wide and 200 meters tall.
The overall area is 300 meters wide by 200 meters tall.
Answer
the answer is -7
Step-by-step explanation: −(16−9)
=-7
<h3>Given</h3>
S = πr√(r^2+h^2)
h = 8 m (constant)
<h3>Find</h3>
An approximation of S when r changes from 9 to 8.9
<h3>Solution</h3>
Such an approximation is usually made by estimating the change using the first derivative. That derivative with respect to r is
... S' = π√(r^2+h^2) + πr(1/2·r)/√(r^2+h^2)
... S' = π(2r^2 +h^2)/√(r^2 +h^2) . . . . . use a common denominator
For r=9, h=8, this is
... S' = π(2·81 +64)/√(81+64) = 226π/√145 ≈ 58.96
Then the change in lateral surface area will be approximately
... ∆S ≈ (∆r)·S' ≈ (-0.1)·(58.96) ≈ -5.90 . . . m²