4/5 of the original amount at the start of the month will remain. The amount at the start of every month will change. Thus:
an = 4/5 (an-1) ; where a1 = 500.
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Given:
Atul has lb of candy.
Jose has lb of candy.
Maria has lb less than Jose.
To find:
How many more pounds of candy does Atul have than Maria?
Solution:
Since, Maria has lb less than Jose, therefore
Maria has = lb
Maria has = lb
Maria has = lb
Difference between the candies Atul and Maria have.
Difference = lb
Difference = lb
Difference = lb
Therefore, Atul have lb of candy more than Maria.
PL= sqrt(4^2+12^2)=4sqrt(1+9)=4sqrt(10)
Using similarity gives that AM=4/3.
ML=40/3
[PLMU]=40/3 * 4 = 160/3 (53.33)
Or
PM= sqrt(4^2+16/9)=sqrt(160/9)=4sqrt(10)/3
4sqrt(10)*4sqrt(10)/3=160/3 or approximately 53.33