Answer:
64.65% probability of at least one injury commuting to work in the next 20 years
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Each day:
Bikes to work with probability 0.4.
If he bikes to work, 0.1 injuries per year.
Walks to work with probability 0.6.
If he walks to work, 0.02 injuries per year.
20 years.
So
Either he suffers no injuries, or he suffer at least one injury. The sum of the probabilities of these events is decimal 1. So
We want . Then
In which
64.65% probability of at least one injury commuting to work in the next 20 years
Answer:
probably the furthest graph to the left.
Step-by-step explanation:
seems like a 25% 10% split.
To solve, we will follow the steps below:
3x+y=11 --------------------------(1)
5x-y=21 ------------------------------(2)
since y have the same coefficient, we can eliminate it directly by adding equation (1) and (2)
adding equation (1) and (2) will result;
8x =32
divide both-side of the equation by 8
x = 4
We move on to eliminate x and then solve for y
To eliminate x, we have to make sure the coefficient of the two equations are the same.
We can achieve this by multiplying through equation (1) by 5 and equation (2) by 3
The result will be;
15x + 5y = 55 ----------------------------(3)
15x - 3y =63 --------------------------------(4)
subtract equation (4) from equation(3)
8y = -8
divide both-side of the equation by 8
y = -1
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Step-by-step explanation:
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Answer:
y=-x-2
Step-by-step explanation:
y+5=-(x-3)
y+5=-x+3
y=-x+3-5
y=-x-2