<span>2x^2 - 19x - 33 = 0 </span>
<span>The factors of 2 are 1 x 2. </span>
<span>The factors of 33 are 1 x 33 and 3 x 11. </span>
<span>Using Guess and Test and FOIL, find a combination that gives you a middle term of -19x: </span>
<span>(2x + 3)(x - 11) = 0. </span>
<span>Using the principal of zero product, solve each equation for x: </span>
<span>2x + 3 =0 and x - 11 =0. </span>
<span>The two solutions are x = -3/2 and x = 11.
</span>
Answer:
x<_2
Step-by-step explanation:
first off solve this like a regular equation the >_ dosent matter till later
so basically first multiply - by 13 and -x so you get -13 and x (multiplying two negatives = a positive)
so its 5x-13+x>_9x-7
add 5x and x to get 6x-13 on one side
then you get 6x-13>_9x-7 then subtract -9x from both sides
so its now -3x-13>_-7 add 13 so you get -3x>_6
then divide both sides by -3 (when you divide an equation with a >< or <_ >_ by a negative number that sign switches) so it will now be x<_2
that your final answer hope this helps :)
Answer:
2
Step-by-step explanation:
Hope this helps, been doing it all my life! :P
Answer:
124
Step-by-step explanation:
because yes
