Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5
final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5
so the final exams has the largest IQR
The formula for probability is # of favorable outcomes divided by the total number of outcomes.
So we know that there are a total of 5 letters. The child writes two letters, so we will have x/5 * x/5. Now, it is asking, what is the probability that they are both vowels.
We can see that a, i, and e are vowels, so the probability if the child were to write one letter would be 3/5. Since he is writing 2, you can multiply 3/5 * 3/5, which would give you your answer, 9/25. Therefore the probability that both letters are vowels is 9/25.
Hope this helps! Please rate, leave a thanks, and mark a brainliest answer. (Not necessarily mine). Thanks, it really helps! :D
That is a 30 60 90 triangle
The "short" side (DE) equals the middle side (FE) times (1 / sq rt(3))
short side = 8 * sqrt(3) * (1 / sq rt(3) = 8
Hypotenuse (DF) is 2 times the short side which equals 16.
Source:
http://www.1728.org/trig2.htm
