All categories

2 years ago

. CDEF is a trapezium

Mathematics

1 answer:

guajiro [1.7K]2 years ago

3 0

9514 1404 393

Answer:

24 cm²

Step-by-step explanation:

To find the area of the trapezium, we must know the length CD. That means we must know the length BC. Fortunately, the perimeter of ABCF is given, so we have ...

P = 2(AB +BC)

BC = (P/2) -AB = (20 cm)/2 - 6 cm = 4 cm

Then CD is ...

CD = BD -BC = 9 cm -4 cm = 5 cm

The area of the trapezium is given by the formula ...

A = (1/2)(b1 +b2)h

A = (1/2)(5 cm + 3 cm)(6 cm) = 24 cm²

The area of trapezium CDEF is 24 cm².

You might be interested in

What is the factorization of 729^15+1000

Nesterboy [21]

$\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) \\\\ a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} 729=27^2\\ \qquad (3^3)^2\\ 1000=10^3 \end{cases}\implies 729^{15}+1000\implies ((3^3)^2)^{15}+10^3 \\\\\\ ((3^2)^{15})^3+10^3\implies (3^{30})^3+10^3\implies (3^{30}+10)~~[(3^{30})^2-(3^{30})(10)+10^2] \\\\\\ (3^{30})^3+10^3\implies (3^{30}+10)~~~~[(3^{60})-(3^{30})(10)+10^2]$

now, we could expand them, but there's no need, since it's just factoring.

3 0

2 years ago

Which expression represents the phrase, "one fifth the sum of 14 and a number"?

Mkey [24]

Answer:

1/5(14+×)

Step-by-step explanation:

The sum of 14 and x has to be (14+x)

5 0

3 years ago

Find the vertical asymptotes, if any, of the graph of the rational function.

miv72 [106K]

Answer:

There is a vertical asymptote for the rational function at x = −4. Set the denominator equal to 0 and solve for x.

2x + 8 = 0 → x = −4

Step-by-step explanation:

3 0

2 years ago

WHAT IS 52÷467 I NEED TO KNOW CAUSE I HAVE TO GET MY GRADES UP

Bond [772]

Answer:

.1113490364

Step-by-step explanation:

this is the answer.

7 0

3 years ago

Solve the quadratic equation 3x²-3x-1=0?<br>(by using the square method)

ohaa [14]

Answer:

x=1 and x=-1/3

Step-by-step explanation:

$3x^2-2x-1=0\\\\3(x^2-\frac{2}{3}x-\frac{1}{3})=0\\ \\3(x^2-\frac{2}{3}x-\frac{1}{3}+\frac{4}{9})=3(\frac{4}{9})\\ \\ 3(x^2-\frac{2}{3}x+\frac{1}{9})=\frac{4}{3}\\ \\ 3(x-\frac{1}{3})^2=\frac{4}{3}\\ \\(x-\frac{1}{3})^2=\frac{4}{9}\\ \\x-\frac{1}{3}=\pm\frac{2}{3}$

$x-\frac{1}{3}=\frac{2}{3}\\ \\x=\frac{3}{3}\\ \\x=1$

$x-\frac{1}{3}=-\frac{2}{3}\\ \\x=-\frac{1}{3}$

Therefore, x=1 and x=-1/3

8 0

2 years ago