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2 years ago

An equation is shown below:

Mathematics

2 answers:

babymother [125]2 years ago

8 0

Answer:

x=1

Step-by-step explanation:

5(2x - 8) + 15 = -15

Distribute

10x -40 +15 = -15

Combine like terms

10x -25 = -15

Add 25 to each side

10x -25+25 = -15+25

10x =10

Divide by 10

10x/10 = 10/10

x=1

HACTEHA [7]2 years ago

5 0

Answer:

You would Use the order of operations

Step-by-step explanation:

first solve what's inside of the parentheses (2x - 8)

then solve multiplication 5 × (2x - 8)

and finally solve addition + 15

and that will equal -15

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What is 2 2/5×2 7/9 in simplest mixed number form?

Scorpion4ik [409]

Answer:

6 2/3

Step-by-step explanation:

2 2/5 * 2 7/9

Change each number to an improper fraction

2 2/5 = (5*2+2)/5 = 12/5

2 7/9 = (9*2+7) = 25/9

12/5 * 25/9

Rewriting

25/5 * 12/9

5/1 * 4/3

20/3

Now changing to a mixed number

3 goes into 20 6 times with 2 left over

6 2/3

7 0

3 years ago

I am giving away points if you answer this Question<br><br> What is 2+2

Setler79 [48]

Answer:

4 heh

Step-by-step explanation:

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6 0

2 years ago

Read 2 more answers

A customer went to a garden shop and bought some potting soil for $12.50 and 5 shrubs. The total bill was $62.50. Write and solv

lesya692 [45]

Answer: Equation: $5x = 62.50 - 12.50$ or $x = \frac{62.50-12.50}{5}$

x is the cost of each shrub x = $10

Step-by-step explanation: Total bill = $62.50.

Subtract the cost of potting soil for $12.50 to find the cost of just the shrubs. 5x equals that amount

5x = 62.50 - 12.50

5x = 50 divide both sides by 5

5x/5 = 50/5

x = 10

6 0

2 years ago

A car is speeding at 9595 miles per hour. How many meters per minute is the vehicle travelling?

sergejj [24]

This is the concept of rates, we are required to convert on rate to another. The We have been given a car that is speeding at 9595 mph, we are required to convert this to meters per minute;
Here we proceed as follows;
1 mile= 1609.34 miles/hour
1 hour= 60 min
thus to convert from miles per hour to meters per minute we shall have:
speed=distance/time
our distance will be:
distance=9595*1609.34=15,441,617.3 meters
time=(60*1)=60 minutes
thus;
speed=15,441,617.3/60
speed=257,360.2882 meters per minuts

4 0

3 years ago

Use Lagrange multipliers to find the maximum and minimum values of (i) f(x,y)-81x^2+y^2 subject to the constraint 4x^2+y^2=9. (i

sp2606 [1]

i. The Lagrangian is

$L(x,y,\lambda)=81x^2+y^2+\lambda(4x^2+y^2-9)$

with critical points whenever

$L_x=162x+8\lambda x=0\implies2x(81+4\lambda)=0\implies x=0\text{ or }\lambda=-\dfrac{81}4$

$L_y=2y+2\lambda y=0\implies2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_\lambda=4x^2+y^2-9=0$

If $x=0$ , then $L_\lambda=0\implies y=\pm3$ .
If $y=0$ , then $L_\lambda=0\implies x=\pm\dfrac32$ .
Either value of $\lambda$ found above requires that either $x=0$ or $y=0$ , so we get the same critical points as in the previous two cases.

We have $f(0,-3)=9$ , $f(0,3)=9$ , $f\left(-\dfrac32,0\right)=\dfrac{729}4=182.25$ , and $f\left(\dfrac32,0\right)=\dfrac{729}4$ , so $f$ has a minimum value of 9 and a maximum value of 182.25.

ii. The Lagrangian is

$L(x,y,z,\lambda)=y^2-10z+\lambda(x^2+y^2+z^2-36)$

with critical points whenever

$L_x=2\lambda x=0\implies x=0$ (because we assume $\lambda\neq0$ )

$L_y=2y+2\lambda y=0\implies 2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_z=-10+2\lambda z=0\implies z=\dfrac5\lambda$

$L_\lambda=x^2+y^2+z^2-36=0$

If $x=y=0$ , then $L_\lambda=0\implies z=\pm6$ .
If $\lambda=-1$ , then $z=-5$ , and with $x=0$ we have $L_\lambda=0\implies y=\pm\sqrt{11}$ .

We have $f(0,0,-6)=60$ , $f(0,0,6)=-60$ , $f(0,-\sqrt{11},-5)=61$ , and $f(0,\sqrt{11},-5)=61$ . So $f$ has a maximum value of 61 and a minimum value of -60.

5 0

2 years ago