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Serga [27]
3 years ago
13

Help me find the slope to 0,0 and 6,1

Mathematics
2 answers:
Molodets [167]3 years ago
5 0

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Slopes and gradient.

slope, m = y2-y1/ x2-x1

hence, m = 1-0/ 6-0

m = 1/6

hence slope = 0.166

boyakko [2]3 years ago
4 0
The guy above is correct

But wouldn’t want to make you waste your points so now I will get them.

Thank you!!!
You might be interested in
4. Determine the following for the equation y = vx – 1.
solniwko [45]

Answer:

this isnt the answer but it helps solve the equation so here is a little explanation

Step-by-step explanation:

Cost Equation

-Is a mathematical equation for a straight line, to predict total cost.

-Total cost = total variable cost + total fixed cost or Y = vx + f

-Y = total mixed cost

v = variable cost per unit of activity

x = volume of activity

f = fixed cost over a given period of time

6 0
3 years ago
There are 162 magazines and books in a library. There are 54 more books
Strike441 [17]

Answer:

108 books.

Step-by-step explanation:

Let the number of magazines = m

Let the number of books = b

<u>Given the following data;</u>

Total number of m & b = 162

<em>Translating the word problem into an algebraic equation, we have;</em>

b = m + 54 ......equation 1

m + b = 162 ......equation 2

<em>Substituting equation "1" into equation "2" we have;</em>

m + m + 54 = 162

2m + 54 = 162

2m = 162 - 54

2m = 108

m = \frac {108}{2}

m = 54

Now to find the number of books;

b = m + 54

Substituting the value of "m" into the equation, we have;

b = 54 + 54

<em>b = 108</em>

<em>Therefore, the total number of books in the library is 108 books. </em>

7 0
3 years ago
Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id
Thepotemich [5.8K]

\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

Explanation

\frac{1}{a+bi}=c+di

Step 1

multiplicate by the conjugate

\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}

notice that

\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\  \end{gathered}\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

I hope this helsp you

6 0
1 year ago
Rectangle Given:1=15 m, w=6m,A=​
sashaice [31]

Answer:

90m^2 and 144 m^2

Step-by-step explanation:

Given :

Length of the rectangle (l)=15m

Width of the rectangle (w)= 6 m

Area of the rectangle can be calculated as :

A=l*w\\A=(15)(6)\\A=90 m^2

Now,

Side of square (s)=12 m

Area of the square can be find:

A=s^2\\A=12^2\\A=144 m^2

6 0
2 years ago
The answer I neeed it now
slava [35]
Anser is B). Subtract smallest number
5 0
3 years ago
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