So we have a 6 at the bottom, and the root is 3, so hmm how to take it out, simple enough, just let's get something to make the 6 a 6³, so it comes out of the root
so
Answer:
318
Step-by-step explanation:
318 is the required answer
I hope it helped you
So given Figure we need to find total surface area
=Area(ABCD)+Area(BCRQ)+Area(QRSP)+Area(ADSP)+Area(ABQP)+Area(DCRS)
=(AB×BC)+(BC×CR)+(QR×RS)+(AD×DS)+(AB×BQ)+(DC×CR)
From figure,
AB=DC=PQ=SR=9 cm
BQ=CR=AP=DS=11 cm
BC=AD=QR=SP=3 cm
On substituting these values We get
Surface Area=(9×3)+(3×11)+(9×3)+(11×3)+(9×11)+(9×11)
=27+33+27+33+99+99=318
I hope it helped you
19.00 3.50 11.00 4.47 makes it add up to hours so that will be answe C
9514 1404 393
Answer:
The given graph shows a function of x.
Step-by-step explanation:
Neither 1 nor 3 is a single-valued relation for some values of x. The graph shown passes the vertical line test, so does represent a function.
The graph is a relation that is a function of x.
___
The attached graph is of the equation of 3. A vertical line will intersect the graph in more than one place, so the relation is NOT a function.
Answer:
Step-by-step explanation:
y₂₋y₁ / x₂-x₁ if you have two points you can plug them in and find the slope using this.
If it is on a graph you can look at two points and count the rise over run, for example if one point is (0, 0) and another is (2, 3) then from the first point it goes up 2 and over 3, so the slope would be 2/3