The length of rectangular pool is 6 ft and width of rectangular pool is 2 ft.
Step-by-step explanation:
Given,
Area of rectangular pool = 12 square feet
Let,
Width of pool = w
Length of pool = l = 2w+2
Area = Length * Width
Dividing each term by 2;
Either,
w+3 = 0 => w=-3
Or,
w-2=0 =>w=2
As width cannot be negative, therefore,
Width of rectangular pool = 2 ft
Length of rectangular pool = 2w+2 = 2(2)+2 = 4+2 = 6 ft
The length of rectangular pool is 6 ft and width of rectangular pool is 2 ft.
Keywords: rectangle, area
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The answer is a because it is open circle
Answer:
10c = 20
5c = 5
Step-by-step explanation:
Let x be the number of 10c coins; let y be the number of 5c coins. The total is $2.25, so the amount of 10c and 5c coins will add to that. Simita has 25 coins, so x and y, the number of coins, will have to add to 25. Hence, solve the simultaneous equation.
10x + 5y = 225 (1) - times by 0
x + y = 25 (2) - times by 5
10x + 5y = 225 (1)
5x + 5y = 125 (2)
Then, take equation 2 away from equation 1.
5x = 100
x = 20
Substitute x back into the original equation.
x + y = 25
20 + y = 25
y = 5
Answer:
f(10)=sqrt(14)
Step-by-step explanation:
f(10) = sqrt(2x-6)
f(10)= sqrt(20-6)
f(10)=sqrt(14) - simplest form, no way to factor it.
Answer:
who is that ? :/
Step-by-step explanation:
