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2 years ago

Y=x^2 -10x+25 number of solutions

Mathematics

1 answer:

kozerog [31]2 years ago

6 0

Answer:

Step-by-step explanation:

First we have to factor:

-5 * -5 equals 25 and adds up to -10.

(x - 5)(x - 5)

The only answer is positive 5, so there is only 1 solution.

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Which equation will create a system of equations with infinitely many solutions?

SashulF [63]

Answer:

A and D

Step-by-step explanation:

for infinitely many solutions, ratio of coefficients should be equal.

since ratio = 1/4 so they will have infinitely many solutions.

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2 years ago

Suski is making lemonade to bring to the beach. She has two containers. One holds one gallon and the other holds 6 quarts. If sh

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2 years ago

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Suppose 360 nursing students took a certification test that is worth 140 points. The five-number summary for the scores is shown

Alenkinab [10]

Quartile 3 is 130. Seventy-five percent of the data lies below Q3.
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2 years ago

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Cuál será la razón entre la cantidad de lejía y la cantidad de agua, si la taza contiene 200 ml (mililitros) y cada litro es 100

tatyana61 [14]

Answer:

Ratio of bleach and water = 1:4

Relación de lejía y agua = 1:4

Step-by-step explanation:

English Translation

What will be the ratio between the amount of bleach and the amount of water, if the filled, 1 L cup contains 200 ml (milliliters) of bleach and each liter is 1000 ml (milliliters)

The cup contains 1000 mL of liquid.

The cup contains 200 mL of bleach and given that the rest is water, there are (1000 - 200) mL of water in the cup.

Amount of bleach in cup = 200 mL

Amount of water in cup = 800 mL

Ratio of bleach to water = 200:800

divide by the least number

Ratio of bleach to water = 1:4

In Spanish/En español

La taza contiene 1000 ml de líquido. La taza contiene 200 ml de lejía y dado que el resto es agua, hay (1000 - 200) ml de agua en la taza.

Cantidad de lejía en taza = 200 ml

Cantidad de agua en taza = 800 ml

Relación de lejía a agua = 200:800

dividir por el menor número

Relación de lejía a agua = 1:4

Hope this Helps!!!

8 0

3 years ago

Pre-calc questions (trignometry)

miv72 [106K]

Answer: (1a) 250° (1b) 70° (2) see below

<u>Step-by-step explanation:</u>

1a) -110 + 360 (one rotation clockwise) = 250°

1b) 430 - 360 (one rotation counterclockwise) = 70°

2) sec Ф = -8/5 in Quadrant III

Quadrant III identifies that both sin (y) and cos (x) are negative.

sec = r/x --> r = 8, x = -5, and y = -√39

(Use Pythagorean Theorem x² + y² = r² to solve for y)

$\sin\theta=\dfrac{y}{r}=\dfrac{-\sqrt{39}}{8}$ $\csc\theta=\dfrac{r}{y}=\dfrac{-8}{\sqrt{39}}$ rationalized = $\dfrac{-8\sqrt{39}}{39}$

$\cos\theta=\dfrac{x}{r}=\dfrac{-5}{8}$ $\sec\theta=\dfrac{r}{x}=\dfrac{-8}{5}$ (GIVEN)

$\tan\theta=\dfrac{y}{x}=\dfrac{\sqrt{39}}{5}$ $\cot\theta=\dfrac{x}{y}=\dfrac{-5}{-\sqrt{39}}$ rationalized = $=\dfrac{5\sqrt{39}}{39}$

NOTE THAT YOU ARE ALLOWED A MAXIMUM OF 3 QUESTIONS PER POST. Please repost #3 and #4 as a different question and I will answer them.

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2 years ago