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Radda [10]
3 years ago
12

Y=x^2 -10x+25 number of solutions

Mathematics
1 answer:
kozerog [31]3 years ago
6 0

Answer:

1

Step-by-step explanation:

First we have to factor:

-5 * -5 equals 25 and adds up to -10.

(x - 5)(x - 5)

The only answer is positive 5, so there is only 1 solution.

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List the common factors of 72 and 36
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3 years ago
Find x , the angle of depression from the top of a lighthouse that is 173 ft above water level to the waterline of a ship 1119 f
gregori [183]

Answer:

arc tan (angle) = 1,119 / 173

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Step-by-step explanation:

3 0
3 years ago
A superhero is trying to leap over a tall building. The function f(x)=-16x^2+200x gives the superhero's height in feet as a func
Gemiola [76]

Answer:

Since \bigtriangleup \geq 0, the superhero makes it over the building.

Step-by-step explanation:

The height is given by the following function:

f(x) = -16x^{2} + 200x

Will the superhero make it over the building?

We have to find if there is values of x for which f(x) = 612.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

If \bigtriangleup < 0, the polynomial has no solutions.

In this question:

f(x) = -16x^{2} + 200x

-16x^{2} + 200x = 612

16x^{2} - 200x + 612 = 0

We have to find \bigtriangleup

We have that a = 16, b = -200, c = 612. So

\bigtriangleup = (-200)^{2} - 4*16*612 = 832

Since \bigtriangleup \geq 0, the superhero makes it over the building.

7 0
3 years ago
Please answer. Thx.
VikaD [51]
A scale map is not an actucal size its a small size we can see
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3 years ago
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Please help it’s just for A4 ignore All the other problems the equation is c=0.15t+2.50
Semmy [17]

Answer:    sds\\ \\ x^{2} \geq \int\limits^a_b {x} \, dx  \lim_{n \to \infty} a_n \geq \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \pi \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right. x^{2}  \lim_{n \to \infty} a_n \pi \neq \sqrt{x} \neq

Step-by-step explanation:i need the think points

4 0
3 years ago
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