Answer:
the salt dissolves in water because of covalent bonds.
Explanation:
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Answer:
14.0 g
Explanation:
Step 1: Write the balanced equation
2 Cu₂O + Cu₂S ⇒ 6 Cu + SO₂
Step 2: Calculate the moles corresponding to 10.5 g of copper (I) oxide
The molar mass of Cu₂O is 143.09 g/mol.
Step 3: Calculate the moles of copper produced from 0.0734 moles of copper (I) oxide
The molar ratio of Cu₂O to Cu is 2:6. The moles of Cu produced are 6/2 × 0.0734 mol = 0.220 mol
Step 4: Calculate the mass corresponding to 0.220 mol of copper
The molar mass of Cu is 63.55 g/mol.
1mol ------------ 3×6,02×10²³ oxygen atoms
x ------------ 2,55×10²⁴
x = 2,5×10²⁴ × 1mol / 3×6,02×10²³ ≈ 0,138*10 mol = 1,38mol
Answer:
See explanation below.
Explanation:
We can obtain the Gibb's free energy from the formula;
∆G= ∆H - T∆S
Where;
∆G = change in free energy= the unknown
∆H= change in enthalpy = 3352 kJ
∆S= change in entropy of the solution= 625.1 J/K
T= absolute temperature = 298 K
Substituting values;
∆G= 3352 ×10^3 J - (298 K × 625.1 J/K)
∆G= 3352 ×10^3 J - 186279.8
∆G= 3.16 × 10^6 J
At 5975K,
∆G= ∆H - T∆S
∆G= 3352 ×10^3 J - (5975K × 625.1 J/K)
∆G= 3.352 ×10^6 J - 3.735 × 10^6
∆G= -3.83×10^5 J
At equilibrium, ∆G=0, Teq is given by;
0= 3352 ×10^3 J - (Teq × 625.1 J/K)
0= 3352 ×10^3 - 625.1Teq
625.1Teq = 3352 ×10^3
Teq= 3352 ×10^3/625.1
Teq= 5362.3 K
Answer:
this isn't an answer just need these points
Explanation: