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alekssr [168]
3 years ago
8

Which phrase describes the charge and mass of a neutron? 1. a charge of +1 and no mass 2. a charge of +1 and an approximate mass

of 1 u 3. no charge and no mass 4. no charge and an approximate mass of 1 u
Chemistry
2 answers:
gtnhenbr [62]3 years ago
6 0

Your answer would be 4. no charge and an approximate mass of 1 u

Tems11 [23]3 years ago
4 0

Answer:

4. no charge and an approximate mass of 1 u

Explanation:

A neutron is present inside the nucleus of an atom just like a proton with a basic difference that it does not have any charge like proton which has +1 charge. The mass of a neutron is almost equivalent to that of a proton which is approximately 1 a.m.u. The atomic mass of an atom is sum total of the mass of neutrons and protons present inside the nucleus of that atom.

But, atomic number of an atom is either equal to the number of protons or number of electrons present in that atom because in a neutral atom there are equal number of protons and  electrons. Electrons do not have any mass so they only contribute to charge in the atom which is -1 for each electron.

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Which of the titanium-containing minerals rutile (TiO2) or ilmenite (FeTiO3) has the larger percentage of titanium?
cupoosta [38]

Rutile (TiO2) or ilmenite (FeTiO3) titanium-containing minerals  has the larger percentage of titanium is explained below.

Explanation:

1. Titanium is obtained from different ores that occur naturally on the Earth. Ilmenite (FeTiO3) and rutile (TiO2) are the most important sources of titanium.

2. According to USGS, Ilmenite(FeTio3) accounts for about 92% of the world’s consumption of titanium minerals.

3. World resources of anatase, ilmenite and rutile total more than 2 billion tonnes. Identified reserves total 750 million tonnes (ilmenite plus rutile).

4. China, with 20 million tonnes--accounting for 29% of the world total-- is now the country that is most abundant in terms of ilmenite reserves. Meanwhile, Australia, with 24 million tones rutile reserves—accounting for 50% of the world total—is now the country that is most abundant in terms of rutile reserves.

5.Ilmenite can be mined from both layered intrusive deposits and heavy mineral deposits. It is often found alongside rutile in heavy mineral deposits. Ilmenite is used to make titanium dioxide  pigment or it can be processed into feedstock that can be used in the manufacture of titanium. This has become more common as viable rutile deposits become increasingly scarce. South Africa and Australia are among the world’s largest producer of Ilmenite, each extracting over a million metric tonnes per year.

6.The Mining of titanium from intrusive rock is restricted to ilmenite and its weathered derivative leucoxene. The largest opencast ilmenite mine is Tellnes in Norway’s municipality of Sokndal.

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Answer:

C

Explanation:

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Which will most likely result if the levels of dissolved oxygen decrease in a body of water?
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B) Native fish species will begin to decrease in population size.

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Which one is correct
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Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 Pb(ClO3)2 with aqueous NaI . NaI. Include phases. chemica
FinnZ [79.3K]

<u>Answer:</u> The mass of precipitate (lead (II) iodide) that will form is 119.89 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of NaI solution = 0.130 M

Volume of solution = 0.400 L

Putting values in above equation, we get:

0.130M=\frac{\text{Moles of NaI}}{0.400L}\\\\\text{Moles of NaI}=(0.130mol/L\times 0.400L)=0.52mol

The balanced chemical equation for the reaction of lead chlorate and sodium iodide follows:

Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)

The precipitate (insoluble salt) formed is lead (II) iodide

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, 0.52 moles of NaI will produce = \frac{1}{2}\times 0.52=0.26mol of lead (II) iodide

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of lead (II) iodide = 0.26 moles

Molar mass of lead (II) iodide = 461.1 g/mol

Putting values in above equation, we get:

0.26mol=\frac{\text{Mass of lead (II) iodide}}{461.1g/mol}\\\\\text{Mass of lead (II) iodide}=(0.26mol\times 461.1g/mol)=119.89g

Hence, the mass of precipitate (lead (II) iodide) that will form is 119.89 grams

4 0
3 years ago
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