Answer:
The answer to your question is Aluminum
Explanation:
We need to warm from 22°C to 85°C
a) 45 g of water
b) 200 g of aluminum Cp = 0.905 J/cal°C
a) Water
Q = mCpΔT
Q = (45)(1)(85 - 22) = 45(63) = 2835 cal
b) Aluminum
Q = (200)(0.905)(85 - 22) = 114030 cal
Answer:
Partial pressure O₂ = 1.78 atm
Explanation:
We can apply the mole fraction to solve the question:
Moles of gas / Total moles = Partial pressure of gas / Total pressure
Total moles = 1 H₂ + 2.5 He + 2O₂ = 4.5 moles
2 mol O₂ / 4.5 mol = Partial pressure O₂ / 4 atm
(2 mol O₂ / 4.5 mol ) . 4 atm = Partial pressure O₂ → 1.78 atm
Answer:
your simpal answer is 177.32
