5x + 10y = 50
x + y = 8
x = 8 - y
5*(8-y) + 10y = 50
40 - 5y + 10y = 50
10y - 5y = 50 - 40
5y = 10
y = 2
x + y = 8
x + 2 = 8
x = 8 - 2
x = 6
She has 6 nickels and 2 dimes
Answer:
Step-by-step explanation:
given that Etsy is an e-commerce website focused on handmade or vintage items and supplies, as well as unique factory-manufactured items. A shop owner on Etsy sells printed t-shirts and she wants to know what level of inventory she should maintain for the month of January. She gathers the January inventories of 8 other shop owners who sell printed t-shirts on Etsy. Their t-shirt inventories are listed below.
59 84 90 54 42 45 77 85
a) Mean = total /8 = 536/8 = 67
For median arrange in ascending order
42 45 54 59 77 84 85 90
Middle entries are 59 and 77
b) Median = average of 59 and 77 = 68
c) If highest changes to 100, data set becomes
42 45 54 59 77 84 85 100
sum increases by 10 i.e. 546
Mean = 546/8 = 68.25
Median will not change remain the same = 68
Mean increases and median stays the same
d) If Var = 369.1429
std dev = square root of variance
= 19.2131
e) Part b answer is the II quartile
f) Mean = 67 and median = 68
Mean < median
So negatively skewed shape
Answer:
Step-by-step explanation:
Hello!
The variable of study is X: Temperature measured by a thermometer (ºC)
This variable has a distribution approximately normal with mean μ= 0ºC and standard deviation σ= 1.00ºC
To determine the value of X that separates the bottom 4% of the distribution from the top 96% you have to work using the standard normal distribution:
P(X≤x)= 0.04 ⇒ P(Z≤z)=0.04
First you have to use the Z tables to determine the value of Z that accumulates 0.04 of probability. It is the "bottom" 0.04, this means that the value will be in the left tail of the distribution and will be a negative value.
z= -1.75
Now using the formula of the distribution and the parameters of X you have to transform the Z-value into a value of X
z= (X-μ)/σ
z*σ = X-μ
(z*σ)+μ = X
X= (-1.75-0)/1= -1.75ºC
The value that separates the bottom 4% is -1.75ºC
I hope this helps!
