Answer:
b) 95 percent confidence interval for this single-sample t test
[11.64, 16.36]
Step-by-step explanation:
Explanation:-
Given data a study of 62 college students finds that their average interest rate is 14 percent with a standard deviation of 9.3 percent.
Sample size 'n' =62
sample mean x⁻ = 14
sample standard deviation 'S' = 9.3
<u>95 percent confidence interval for this single-sample t test</u>
The values are
the <u>95 percent confidence interval for the population mean 'μ'</u>
Degrees of freedom γ=n-1=62-1=61
t₀.₀₅ = 1.9996 at 61 degrees of freedom

(14-2.361 , 14 + 2.361)
[(11.64 , 16.36]
<u>Conclusion:-</u>
95 percent confidence interval for this single-sample t test
[11.64, 16.36]
<u></u>
Answer:
x = -6
Step-by-step explanation:
Simplifying
3(1.5x + 9) = 0
Reorder the terms:
3(9 + 1.5x) = 0
(9 * 3 + 1.5x * 3) = 0
(27 + 4.5x) = 0
Solving
27 + 4.5x = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-27' to each side of the equation.
27 + -27 + 4.5x = 0 + -27
Combine like terms: 27 + -27 = 0
0 + 4.5x = 0 + -27
4.5x = 0 + -27
Combine like terms: 0 + -27 = -27
4.5x = -27
Divide each side by '4.5'.
x = -6
Simplifying
x = -6