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Sedaia [141]
3 years ago
8

ANYONE up???????????????????????????and can i get help with this

Mathematics
1 answer:
Mashcka [7]3 years ago
8 0

Answer:

here's the solution : -

=》2x - 3y = -29

=》x + 6y = 23

=》x = 23 - 6y

now, plugging the value of x in equation 1, we get : -

=》2x - 3y = -29

=》2 (23 - 6y) - 3y = - 29

=》46 - 12y - 3y = -29

=》-15y = -29 - 46

=》y = -75 ÷ -15

=》y = 5

now, plugging the value of y as 5 in equation 2

=》x + 6y = 23

=》x + (6 × 5.2) = 23

=》x = 23 - 30

=》x = - 7

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Help please with algebra problem
Strike441 [17]
Number of weekend minutes used: x
Number of weekday minutes used: y

This month Nick was billed for 643 minutes:
(1) x+y=643

The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44

We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44

Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y

Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44

Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72

Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243

Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400


Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
6 0
3 years ago
Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex
siniylev [52]

Answer:

\large \boxed{\sf \ \ \ p=-11 \ \ \ }

Step-by-step explanation:

Hello,

\alpha \text{ and } \beta \text{ are the roots of the following equation}

   2x^2+6x-7=p

It means that

   2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\

And we know that

\alpha= 2\cdot \beta

So we got two equations

   2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1

For \beta =0, \ \ \alpha =0, \ \ p = -7

For \beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11

I assume that we are after two different roots so the solution for p is p=-11

b) \alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1

So a quadratic equation with the expected roots  is

x(x-1)=x^2-x

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
3 years ago
A zucchini plant in Darnell’s garden was 10 centimeter y’all when it was first planted since then it has grown approximately 0.5
trapecia [35]

After 17 days

d=numbers of days

10+0.5d=18.5

0.5d=8.5

divide both sides by 0.5

d=17

8 0
3 years ago
19. Martin wants to buy a new CD player. The
Alex777 [14]

Answer:

$131.25

Step-by-step explanation:

175×0.25=43.75

175-43.75=131.25

6 0
3 years ago
PLEASE HELP I DONT UNDERSTAND AND NOBODY WILL HELP ME
Dima020 [189]

Answer:

radius=3

Step-by-step explanation:

volumes of a cone = 1/3πr²h

12π = 1/3× π × r² × 4

37.7 = 12.6r²/3

cross multiply

37.7×3=12.6r²

113.1=12.6r²

make r² subject of the formula

r²=113.1÷12.6

r²=8.976

r=√8.976

r=2.996

r=3.0 (to the nearest tenth)

4 0
2 years ago
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