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Andre45 [30]
3 years ago
13

Find the slope of the line that passes through (7,2) and (3,3)​

Mathematics
2 answers:
Sav [38]3 years ago
8 0

Answer:

1 over 4

Step-by-step explanation:

tatuchka [14]3 years ago
6 0

Answer:

the answer is \frac{1}{-4\\}

Step-by-step explanation:

slope= y_{2}-y_{1}

           x_{2}-x_{1}   so 3-2=1 and then 3-7=-4

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What is the perimeter 2x+3 as length and x-6 as width
Oduvanchick [21]

What is the perimeter 2x+3 as length and x-6 as width

P = 2L + 2W

P = 2(2x+3)+2(x-6)

P = 4x+6 + 2x - 12

P = 6x - 6

<h2>#CarryOnLearning</h2><h2>#LearningIsFun</h2>

5 0
3 years ago
Read 2 more answers
Consider the number pattern -6, -11, -16, -21..... Which term of the pattern =-401?​
steposvetlana [31]

Answer:

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7 0
2 years ago
What is the answer need ASAP
ArbitrLikvidat [17]

ANSWER


C. 58°


EXPLANATION


The sum of the interior angles of a triangle is 180°.


We sum all the three angles to obtain,


8x+(14x+2)+(10x+50)=180.


We group like terms to get,



8x+14x+10x+2+50=180.


Simplify,



32x+52=180.


Combine like terms to get,


32x=180-52.


Simplify,


32x=128.



Divide both sides by 32 to get,



x=4.


We substitute the value of x into the expression for



m\:.


This implies that,


m\:.



m\:.



m\:.



The correct answer is C

8 0
3 years ago
3x - 2(2x - 5) = 2(x + 3) - 8
nataly862011 [7]

Answer:

x = 4

Step-by-step explanation:

Hello!

We can solve for x by expanding the parentheses and isolating x.

<h3>Solve for x</h3>
  • 3x - 2(2x - 5) = 2(x + 3)-8
  • 3x - 4x + 10 = 2x + 6 - 8
  • -x + 10 = 2x - 2
  • 10 = 3x - 2
  • 12 = 3x
  • x = 4

The value of x is 4.

3 0
2 years ago
You invest $2,000 in an account that is compounded annually at an interest rate of 5%. You never withdraw money from the account
castortr0y [4]
Formula for amount for compound interest:
Amount, A =  P(1 + r/100)^n
Where r is rate, P is principal, and n is the number of years.
P = 2000, r = 5, n = t years.
A = 2000( 1 + 5/100)^t
A = 200(1+0.05)^t
A = 2000(1.05)^t
A(t) = 2000(1.05)^t 
6 0
3 years ago
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