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Fudgin [204]
2 years ago
6

The graph shows a square root function. Use what you know about domain to select all of the following functions that could be th

e one graphed f(x) - V-3 0 KG) V-1 f(x)= x+1 Fx) = x3z- 3​

Mathematics
1 answer:
valkas [14]2 years ago
6 0

Answer:

on ed its the first one and the second one

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Please help! I’ve always had trouble with these questions. It’d be a big hand.
deff fn [24]

2. c = 47,000 × n, where c is the cost of n number of bears.

3. a) The cost to ride 5 rides = $20.50, the cost to ride 8 rides = $28.00

The equation for the pattern, C(x) = 15.50 + 2.50 (r - 3), where C is the cost and r is the number of rides.

b) The cost to ride 12 rides = $36.00.

Step-by-step explanation:

Step 1; To find the cost of one bear, we divide the cost of bears by the number.

If 4 bears cost $188,000, 1 bear costs = \frac{188000}{4} = $47,000.

If 7 bears cost $329,000, 1 bear costs = \frac{329,000}{7} = $47,000.

So the equation is c = 47,000 × n, where c is the cost to buy n bears.

Step 2; For every additional ride, the price increases by $2.50. So the equation for the pattern is C(x) = 13.50 + 2.50 (x - 3).

When the number of rides is 5, C(5) = 15.50 + 2.50 (5-3) = 15.50 + 2.50 (2) = 15.50 + 5.0 = $20.50.

When the number of rides is 8, C(8) = 15.50 + 2.50 (8-3) = 15.50 + 2.50 (5) = 15.50 + 12.50 = $28.00.

When the number of rides is 12, C(12) = 15.50 + 2.50 (12-3) = 15.50 + 2.50 (9) = 13.50 + 22.5 = $36.00.

3 0
2 years ago
There are 125 members in the school
Igoryamba

Answer:

125x + 5,000 > 25,000

5 0
2 years ago
Which is the quotient for
mars1129 [50]

Answer:

i think its D

Step-by-step explanation:

D

3 0
3 years ago
Can please answer these 3 questions
kupik [55]
So it would be 32 lol if
6 0
2 years ago
ALGEBRA 2!!!!!!!!! SHOW YOUR WORK!!!!!!!!!!!!!<br> Do f(g(x)) and g(f(x))
bezimeni [28]

\bf f(x)=\cfrac{2x-3}{x+1}~\hspace{10em}g(x)=\cfrac{x+3}{2-x}&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;f(~~g(x)~~)\implies \cfrac{2[g(x)]-3}{[g(x)]+1}\implies \cfrac{2\left( \frac{x+3}{2-x} \right)-3}{\left( \frac{x+3}{2-x} \right)+1}\implies&#10;\cfrac{\frac{2x+6}{2-x}-3}{\frac{x+3}{2-x}+1}&#10;\\\\\\&#10;\cfrac{\frac{2x+6-6+3x}{2-x}}{\frac{x+3+2-x}{2-x}}\implies \cfrac{2x+6-6+3x}{2-x}\cdot \cfrac{2-x}{x+3+2-x}\implies \cfrac{5x}{5}\implies x


\bf \rule{34em}{0.25pt}\\\\&#10;g(~~f(x)~~)\implies \cfrac{[f(x)]+3}{2-[f(x)]}\implies \cfrac{\frac{2x-3}{x+1}+3}{2-\frac{2x-3}{x+1}}\implies \cfrac{\frac{2x-3+3x+3}{x+1}}{\frac{2x+2-(2x-3)}{x+1}}&#10;\\\\\\&#10;\cfrac{2x-3+3x+3}{x+1}\cdot \cfrac{x+1}{2x+2-(2x-3)}\implies \cfrac{2x-3+3x+3}{x+1}\cdot \cfrac{x+1}{2x+2-2x+3}&#10;\\\\\\&#10;\cfrac{5x}{5}\implies x


and in case you recall your inverses, when f(  g(x)  ) = x,  or g(  f(x)  ) = x, simply means, they're inverse of each other.

4 0
3 years ago
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