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MrRissso [65]
3 years ago
11

Find the missing values for each of the following 3 questions

Mathematics
1 answer:
Tomtit [17]3 years ago
4 0
1.) 10
2.) 60
3.) 80

hope this helps!
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Need help with this question
gulaghasi [49]

Answer:

bc=-4

Step-by-step explanation:

4x -1 is -4. because your adding a negative and a positive

8 0
3 years ago
Read 2 more answers
Can somebody please help me
erik [133]

Answer:

d=3 and e=-1

Step-by-step explanation:

d+e=2

d=2-e-----(1)

d-e=4-----(2)

substituting (1) in (2)

2-e-e=4

-2e=2

e=-1-----(3)

substituting (3) in (1)

d=2-(-1)

d=3

6 0
3 years ago
Please answer with clear instructions so that i can apply this to other questions
Strike441 [17]

Answer:

  x = 2 ,  3/2

Step-by-step explanation:

3 0
2 years ago
If p varies directly with T and p =105 when T=400.Find p when T =500
kumpel [21]

Answer:

<h3>p = 131.25</h3>

Step-by-step explanation:

The variation p varies directly with T is written as

p = kT

where k is the constant of proportionality

To find p when T =500 we must first find the formula for the variation

That's

when p = 105 and T = 400

105 = 400k

Divide both sides by 400

<h3>k =  \frac{21}{80}</h3>

So the formula for the variation is

<h2>p =  \frac{21}{80} T</h2>

when

T = 500

Substitute it into the above formula

That's

p =  \frac{21}{80}  \times 500

Simplify

The final answer is

<h3>p = 131.25</h3>

Hope this helps you

7 0
3 years ago
Twenty five heat lamps are connected in a greenhouse so, that when one lamp fails, another takes over immediately (only one lamp
olga55 [171]

Answer:

P = 0.006

Step-by-step explanation:

Given

n = 25 Lamps

each with mean lifetime of 50 hours and standard deviation (SD) of 4 hours

Find probability that the lamp will be burning at end of 1300 hours period.

As we are not given that exact lamp, it means we have to find the probability where any of the lamp burning at the end of 1300 hours, So we have

Suppose i represents lamps

P (∑i from 1 to 25 (X_i > 1300)) = 1300

= P(X^{'}> \frac{1300}{25})                  where X^{'} represents mean time of a single lamp

= P (Z> \frac{52-50}{\frac{1}{\sqrt{25}}})                Z is the standard normal distribution which can be found by using the formula

Z = Mean Time (X^{'}) - Life time of each Lamp (50 hours)/ (SD/\sqrt{n})

Z = (52-50)/(4/\sqrt{25}) = 2.5

Now, P(Z>2.5) = 0.006 using the standard normal distribution table

Probability that a lamp will be burning at the end of 1300 hours period is 0.006

4 0
3 years ago
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