All categories

2 years ago

How many gallons of pure water should be evaporated from 160 gallons of a solution containing 12% salt

Mathematics

2 answers:

AfilCa [17]2 years ago

6 0

Answer:

66 gallons

Step-by-step explanation:

Given that initially 160 gallons of a solution containing 12% salt.

So, the initial amount of salt = 12% of 160 = 12/100 x 160 = 19.2 gallons.

Let x gallons of water get evaporated so that the remaining solution contains 20% salt.

The remaining amount of solution = 160-x gallons.

As the initial amount of salt is still in the solution which is equal to 20% of the remaining solution, so

19.2 = 20% of (160-x)

$\Rightarrow 19.2 = \frac {20}{100}\times (160-x) \\\\\Rightarrow 19.2 = \frac {1}{5}\times (160-x) \\\\\Rightarrow 19.2 \times 5= 160-x \\\\\Rightarrow 96= 160-x \\\\\Rightarrow x= 160-96 \\\\$

$\Rightarrow x= 66$ gallons

Hence, 66 gallons of water must be evaporated to get a 20% salt solution.

Igoryamba2 years ago

6 0

Answer:

its A, "gallons of pure water"

Step-by-step explanation: just did it on edg and got it right

You might be interested in

Let C be the positively oriented square with vertices (0,0), (1,0), (1,1), (0,1). Use Green's Theorem to evaluate the line integ

liq [111]

Answer:

1/2

Step-by-step explanation:

The interior of the square is the region D = { (x,y) : 0 ≤ x,y ≤1 }. We call L(x,y) = 7y²x, M(x,y) = 8x²y. Since C is positively oriented, Green Theorem states that

$\int\limits_C {L(x,y)} \, dx + {M(x,y)} \, dy = \int\limits^1_0\int\limits^1_0 {(Mx - Ly)} \, dxdy$

Lets calculate the partial derivates of M and L, Mx and Ly. They can be computed by taking the derivate of the respective value, treating the other variable as a constant.

Mx(x,y) = d/dx 8x²y = 16xy
Ly(x,y) = d/dy 7y²x = 14xy

Thus, Mx(x,y) - Ly(x,y) = 2xy, and therefore, the line ntegral is equal to the double integral

$\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy$

We can compute the double integral by applying the Barrow's Rule, a primitive of 2xy under the variable x is x²y, thus the double integral can be computed as follows

$\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy = \int\limits^1_0 {x^2y} |^1_0 \,dy = \int\limits^1_0 {y} \, dy = \frac{y^2}{2} \, |^1_0 = 1/2$

We conclude that the line integral is 1/2

4 0

2 years ago

A falcon flies 300 kilometers per hour. A goose flies 140 kilometers per hour. If a falcon and a goose each fly for 2 hours, how

Mila [183]

Answer:

320

Step-by-step explanation:

Distance covered by falcon in 2 hours=300*2=600 km

Distance covered by goose in 2 hours=140*2=280 km.

Falcon flew 600-280=320 km more than goose

7 0

3 years ago

What is the domain of g?

wariber [46]

Answer:

The answer is -9,9 Its funny cuz I just did this problem on Khan academy

Step-by-step explanation:

Can I get brainliest

5 0

3 years ago

Read 2 more answers

Math problem easy question! Giving brainlist

Oksanka [162]

Answer:

It would be A

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Which of the following is the most profitable investment for a candy shop that earns $1 revenue per pound of candy? (5 points) G

rewona [7]

Then the most profitable investment is the first machine (third option) because for each dollar, it produces 2 pounds of candy.

<h3>Which of the following is the most profitable investment?</h3>

The first option is a worker that costs $10 per hour and produces 8lb, then this worker gives:

8lb/$10= 0.8 pounds per dollar.

The second worker costs $12 per hour, and produces 16lb per hour, so this worker gives:

16lb/$12 = 1.33 pounds per dollar.

The third option is a machine that cost $5 per hour and produces 10lb per hour, then:

10lb/$5 = 2 pound per dollar.

The last option costs $8 per hour, and produces 14 pounds per hour, then:

14lb/$8 = 1.75 pounds per dollar.

Then the most profitable investment is the first machine (third option) because for each dollar, it produces 2 pounds of candy.

If you want to learn more about profit:

brainly.com/question/23103804

#SPJ1

3 0

2 years ago