Some abiotic factors that can limit a population are space and weather these are called limiting factors (and how much water is provided)
Answer:
Brain and spinal cord
Explanation:
Meningitis is the inflammation of the protective covering of the meninges, the three membranes covering the brain and spinal cord. Meningitis usually occurs from a viral infection, but may sometimes result from a bacterial or fungal infection, cancer or drug allergies.
Viral and bacterial meningitis may be contagious and can be transmitted through coughing and sneezing.
Symptoms of meningitis include:
- sensitivity to bright light
Treatment is by vaccination, use of antibiotics and antifungal agents.
Mendel was able to attribute the variation observed in the offspring of his experiment to the controlled fertilization process.
Mendel was able to control pollination and, thus, the fertilization process in the pea plants used for his experiment.
Mendel was able to effectively predict the outcome with self-pollination or cross-pollination with different results coming from each. Thus, he logically concluded that the variation observed in the offspring of his crosses is due to the fact that he controlled the fertilization process.
More on Mendel's experiments can be found here: brainly.com/question/3186121?referrer=searchResults
Answer:
biliverdin
Explanation:
it's biliverdin, hope this helped!
The frequency <em>p</em> of the yellow (A) allele is <em>p</em>= 0.3
The frequency <em>q</em> of the blue (a) allele is <em>q= </em><em>0.7</em>
Hardy–Weinberg equilibrium, states that allele and genotype frequencies in a population will remain constant from generation to generation. Equilibrium is reached in the absence of selection, mutation, genetic drift and other forces and allele frequencies p and q are constant between generations. In the simplest case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes.
p²+2*p*q+q²= 1 p+q= 1 q= 1-p
yellow (p²)= 9%= 0.09 p= √0.09= 0.3
green (2*p*q)= 42%= 0.42
blue (q²)=49%= 0.49 q=1-0.3= 0.7 <em>or</em> q= √0.49= 0.7
